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fix leftover \land
author
Ian Jackson
<ijackson@chiark.greenend.org.uk>
Sun, 25 Mar 2012 19:45:56 +0000
(20:45 +0100)
committer
Ian Jackson
<ijackson@chiark.greenend.org.uk>
Sun, 25 Mar 2012 19:45:56 +0000
(20:45 +0100)
merge.tex
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diff --git
a/merge.tex
b/merge.tex
index 94b38fe9648d88f2022ba9ee57aae96d35806a2e..7a48a25cf994a282b5c1d74d019af0f45aafb7d2 100644
(file)
--- a/
merge.tex
+++ b/
merge.tex
@@
-165,7
+165,7
@@
$D \isin Y \equiv D \le Y$. $D \not\isin X$.
We will show for each of
various cases that
if $M \haspatch \p$, $D \not\isin C$,
-whereas if $M \nothaspatch \p$, $D \isin C \equiv
\land
D \le C$.
+whereas if $M \nothaspatch \p$, $D \isin C \equiv D \le C$.
And by $Y \haspatch \p$, $\exists_{F \in \py} F \le Y$ and this
$F \le C$ so this suffices.