strategy: wip

diff --git a/strategy.tex b/strategy.tex
index a3acc81ec7560dec9a0cd0e9e7b2311ac10a4194..cec63884f8a85ce8fc3ec4fc0fae5019b8ec1f64 100644 (file)
--- a/strategy.tex
+++ b/strategy.tex
@@ -130,16 +130,16 @@ it is, are we fast forward to $E_i$
 and drop $E_i$ from the planned ordering.
 
 Then we will merge the direct contributors and the sources' ends.
-
 This generates more commits $\tipuc \in \pc$, but none in any other
-commit set.  We maintain XXX FIXME IS THIS THE BEST THING?
+commit set.  We maintain
 $$
  \bigforall_{\p \isdep \pc}
- \pancsof{\tipcc}{\p} \subset \left[
-   \tipfa \p \cup
-   \bigcup_{E \in \set E_{\pc}} \pancsof{E}{\p}
-  \right]
+ \pancsof{\tipcc}{\p} \subset
+   \pancsof{\tipfa \p}{\p}
 $$
+\proof{
+ For $\tipcc = \tipzc$, $T$ ...WRONG WE NEED $\tipfa \p$ TO BE IN $\set E$ SOMEHOW
+}
 
 \subsection{Merge Contributors for $\pcy$}
 
@@ -147,16 +147,18 @@ Merge $\pcn$ into $\tipc$.  That is, merge with
 $L = \tipc, R = \tipfa{\pcn}, M = \baseof{\tipc}$.
 to construct $\tipu$.
 
-Merge conditions: Ingredients satisfied by construction.
+Merge conditions:
+
+Ingredients satisfied by construction.
 Tip Merge satisfied by construction.  Merge Acyclic follows
 from Perfect Contents and $\hasdep$ being acyclic.
 
-Removal Merge Ends: For $\p = \pc$, $M \nothaspatch \p$.
-For $p \neq \pc$, by Tip Contents,
+Removal Merge Ends: For $\p = \pc$, $M \nothaspatch \p$; OK.
+For $\p \neq \pc$, by Tip Contents,
 $M \haspatch \p \equiv L \haspatch \p$, so we need only
 worry about $X = R, Y = L$; ie $L \haspatch \p$,
 $M = \baseof{L} \haspatch \p$.
-By Tip Contents for $L$, $D \le L \equiv D \le M$.  $\qed$
+By Tip Contents for $L$, $D \le L \equiv D \le M$.  OK.~~$\qed$
 
 WIP UP TO HERE
 
@@ -167,6 +169,10 @@ $R \haspatch \p$.  So we only need to worry about $Y = R = \tipfa \pcn$.
 By Tip Dependencies $\tipfa \pcn \ge \tipfa \py$.
 And by Tip Sources $\tipfa \py \ge $
 
+want to prove $E \le \tipfc$ where $E \in \pendsof{\tipcc}{\py}$
+
+$\pancsof{\tipcc}{\py} = $
+
 
 computed $\tipfa \py$, and by Perfect Contents for $\py$