*/
/*
- *
- * - There's an interesting deductive technique which makes use of topology
- * rather than just graph theory. Each _square_ in the grid is either inside
- * or outside the loop; you can tell that two squares are on the same side
- * of the loop if they're separated by an x (or, more generally, by a path
- * crossing no LINE_UNKNOWNs and an even number of LINE_YESes), and on the
- * opposite side of the loop if they're separated by a line (or an odd
- * number of LINE_YESes and no LINE_UNKNOWNs). Oh, and any square separated
- * from the outside of the grid by a LINE_YES or a LINE_NO is on the inside
- * or outside respectively. So if you can track this for all squares, you
- * figure out the state of the line between a pair once their relative
- * insideness is known.
+ * Possible future solver enhancements:
+ *
+ * - There's an interesting deductive technique which makes use
+ * of topology rather than just graph theory. Each _face_ in
+ * the grid is either inside or outside the loop; you can tell
+ * that two faces are on the same side of the loop if they're
+ * separated by a LINE_NO (or, more generally, by a path
+ * crossing no LINE_UNKNOWNs and an even number of LINE_YESes),
+ * and on the opposite side of the loop if they're separated by
+ * a LINE_YES (or an odd number of LINE_YESes and no
+ * LINE_UNKNOWNs). Oh, and any face separated from the outside
+ * of the grid by a LINE_YES or a LINE_NO is on the inside or
+ * outside respectively. So if you can track this for all
+ * faces, you figure out the state of the line between a pair
+ * once their relative insideness is known.
+ * + The way I envisage this working is simply to keep an edsf
+ * of all _faces_, which indicates whether they're on
+ * opposite sides of the loop from one another. We also
+ * include a special entry in the edsf for the infinite
+ * exterior "face".
+ * + So, the simple way to do this is to just go through the
+ * edges: every time we see an edge in a state other than
+ * LINE_UNKNOWN which separates two faces that aren't in the
+ * same edsf class, we can rectify that by merging the
+ * classes. Then, conversely, an edge in LINE_UNKNOWN state
+ * which separates two faces that _are_ in the same edsf
+ * class can immediately have its state determined.
+ * + But you can go one better, if you're prepared to loop
+ * over all _pairs_ of edges. Suppose we have edges A and B,
+ * which respectively separate faces A1,A2 and B1,B2.
+ * Suppose that A,B are in the same edge-edsf class and that
+ * A1,B1 (wlog) are in the same face-edsf class; then we can
+ * immediately place A2,B2 into the same face-edsf class (as
+ * each other, not as A1 and A2) one way round or the other.
+ * And conversely again, if A1,B1 are in the same face-edsf
+ * class and so are A2,B2, then we can put A,B into the same
+ * face-edsf class.
+ * * Of course, this deduction requires a quadratic-time
+ * loop over all pairs of edges in the grid, so it should
+ * be reserved until there's nothing easier left to be
+ * done.
+ *
+ * - The generalised grid support has made me (SGT) notice a
+ * possible extension to the loop-avoidance code. When you have
+ * a path of connected edges such that no other edges at all
+ * are incident on any vertex in the middle of the path - or,
+ * alternatively, such that any such edges are already known to
+ * be LINE_NO - then you know those edges are either all
+ * LINE_YES or all LINE_NO. Hence you can mentally merge the
+ * entire path into a single long curly edge for the purposes
+ * of loop avoidance, and look directly at whether or not the
+ * extreme endpoints of the path are connected by some other
+ * route. I find this coming up fairly often when I play on the
+ * octagonal grid setting, so it might be worth implementing in
+ * the solver.
*
* - (Just a speed optimisation.) Consider some todo list queue where every
* time we modify something we mark it for consideration by other bits of
#include <stdio.h>
#include <stdlib.h>
+#include <stddef.h>
#include <string.h>
#include <assert.h>
#include <ctype.h>
#include "puzzles.h"
#include "tree234.h"
#include "grid.h"
+#include "loopgen.h"
/* Debugging options */
COL_HIGHLIGHT,
COL_MISTAKE,
COL_SATISFIED,
+ COL_FAINT,
NCOLOURS
};
struct game_state {
- grid *game_grid;
+ grid *game_grid; /* ref-counted (internally) */
/* Put -1 in a face that doesn't get a clue */
signed char *clues;
* YES, NO or UNKNOWN */
char *lines;
+ unsigned char *line_errors;
+ int exactly_one_loop;
+
int solved;
int cheated;
};
/* ------ Solver state ------ */
-typedef struct normal {
- /* For each dline, store a bitmask for whether we know:
- * (bit 0) at least one is YES
- * (bit 1) at most one is YES */
- char *dlines;
-} normal_mode_state;
-
-typedef struct hard {
- int *linedsf;
-} hard_mode_state;
-
typedef struct solver_state {
game_state *state;
enum solver_status solver_status;
* looplen of 1 means there are no lines to a particular dot */
int *looplen;
+ /* Difficulty level of solver. Used by solver functions that want to
+ * vary their behaviour depending on the requested difficulty level. */
+ int diff;
+
/* caches */
char *dot_yes_count;
char *dot_no_count;
char *dot_solved, *face_solved;
int *dotdsf;
- normal_mode_state *normal;
- hard_mode_state *hard;
+ /* Information for Normal level deductions:
+ * For each dline, store a bitmask for whether we know:
+ * (bit 0) at least one is YES
+ * (bit 1) at most one is YES */
+ char *dlines;
+
+ /* Hard level information */
+ int *linedsf;
} solver_state;
/*
*/
#define DIFFLIST(A) \
- A(EASY,Easy,e,easy_mode_deductions) \
- A(NORMAL,Normal,n,normal_mode_deductions) \
- A(HARD,Hard,h,hard_mode_deductions)
-#define ENUM(upper,title,lower,fn) DIFF_ ## upper,
-#define TITLE(upper,title,lower,fn) #title,
-#define ENCODE(upper,title,lower,fn) #lower
-#define CONFIG(upper,title,lower,fn) ":" #title
-#define SOLVER_FN_DECL(upper,title,lower,fn) static int fn(solver_state *);
-#define SOLVER_FN(upper,title,lower,fn) &fn,
+ A(EASY,Easy,e) \
+ A(NORMAL,Normal,n) \
+ A(TRICKY,Tricky,t) \
+ A(HARD,Hard,h)
+#define ENUM(upper,title,lower) DIFF_ ## upper,
+#define TITLE(upper,title,lower) #title,
+#define ENCODE(upper,title,lower) #lower
+#define CONFIG(upper,title,lower) ":" #title
enum { DIFFLIST(ENUM) DIFF_MAX };
static char const *const diffnames[] = { DIFFLIST(TITLE) };
static char const diffchars[] = DIFFLIST(ENCODE);
#define DIFFCONFIG DIFFLIST(CONFIG)
-DIFFLIST(SOLVER_FN_DECL);
-static int (*(solver_fns[]))(solver_state *) = { DIFFLIST(SOLVER_FN) };
+
+/*
+ * Solver routines, sorted roughly in order of computational cost.
+ * The solver will run the faster deductions first, and slower deductions are
+ * only invoked when the faster deductions are unable to make progress.
+ * Each function is associated with a difficulty level, so that the generated
+ * puzzles are solvable by applying only the functions with the chosen
+ * difficulty level or lower.
+ */
+#define SOLVERLIST(A) \
+ A(trivial_deductions, DIFF_EASY) \
+ A(dline_deductions, DIFF_NORMAL) \
+ A(linedsf_deductions, DIFF_HARD) \
+ A(loop_deductions, DIFF_EASY)
+#define SOLVER_FN_DECL(fn,diff) static int fn(solver_state *);
+#define SOLVER_FN(fn,diff) &fn,
+#define SOLVER_DIFF(fn,diff) diff,
+SOLVERLIST(SOLVER_FN_DECL)
+static int (*(solver_fns[]))(solver_state *) = { SOLVERLIST(SOLVER_FN) };
+static int const solver_diffs[] = { SOLVERLIST(SOLVER_DIFF) };
+static const int NUM_SOLVERS = sizeof(solver_diffs)/sizeof(*solver_diffs);
struct game_params {
int w, h;
int diff;
int type;
-
- /* Grid generation is expensive, so keep a (ref-counted) reference to the
- * grid for these parameters, and only generate when required. */
- grid *game_grid;
};
+/* line_drawstate is the same as line_state, but with the extra ERROR
+ * possibility. The drawing code copies line_state to line_drawstate,
+ * except in the case that the line is an error. */
enum line_state { LINE_YES, LINE_UNKNOWN, LINE_NO };
+enum line_drawstate { DS_LINE_YES, DS_LINE_UNKNOWN,
+ DS_LINE_NO, DS_LINE_ERROR };
#define OPP(line_state) \
(2 - line_state)
int started;
int tilesize;
int flashing;
+ int *textx, *texty;
char *lines;
char *clue_error;
char *clue_satisfied;
};
-static char *validate_desc(game_params *params, char *desc);
+static char *validate_desc(const game_params *params, const char *desc);
static int dot_order(const game_state* state, int i, char line_type);
static int face_order(const game_state* state, int i, char line_type);
-static solver_state *solve_game_rec(const solver_state *sstate,
- int diff);
+static solver_state *solve_game_rec(const solver_state *sstate);
#ifdef DEBUG_CACHES
static void check_caches(const solver_state* sstate);
/* ------- List of grid generators ------- */
#define GRIDLIST(A) \
- A(Squares,grid_new_square) \
- A(Triangular,grid_new_triangular) \
- A(Honeycomb,grid_new_honeycomb) \
- A(Snub-Square,grid_new_snubsquare) \
- A(Cairo,grid_new_cairo) \
- A(Great-Hexagonal,grid_new_greathexagonal) \
- A(Octagonal,grid_new_octagonal) \
- A(Kites,grid_new_kites)
-
-#define GRID_NAME(title,fn) #title,
-#define GRID_CONFIG(title,fn) ":" #title
-#define GRID_FN(title,fn) &fn,
+ A(Squares,GRID_SQUARE,3,3) \
+ A(Triangular,GRID_TRIANGULAR,3,3) \
+ A(Honeycomb,GRID_HONEYCOMB,3,3) \
+ A(Snub-Square,GRID_SNUBSQUARE,3,3) \
+ A(Cairo,GRID_CAIRO,3,4) \
+ A(Great-Hexagonal,GRID_GREATHEXAGONAL,3,3) \
+ A(Octagonal,GRID_OCTAGONAL,3,3) \
+ A(Kites,GRID_KITE,3,3) \
+ A(Floret,GRID_FLORET,1,2) \
+ A(Dodecagonal,GRID_DODECAGONAL,2,2) \
+ A(Great-Dodecagonal,GRID_GREATDODECAGONAL,2,2) \
+ A(Penrose (kite/dart),GRID_PENROSE_P2,3,3) \
+ A(Penrose (rhombs),GRID_PENROSE_P3,3,3)
+
+#define GRID_NAME(title,type,amin,omin) #title,
+#define GRID_CONFIG(title,type,amin,omin) ":" #title
+#define GRID_TYPE(title,type,amin,omin) type,
+#define GRID_SIZES(title,type,amin,omin) \
+ {amin, omin, \
+ "Width and height for this grid type must both be at least " #amin, \
+ "At least one of width and height for this grid type must be at least " #omin,},
static char const *const gridnames[] = { GRIDLIST(GRID_NAME) };
#define GRID_CONFIGS GRIDLIST(GRID_CONFIG)
-static grid * (*(grid_fns[]))(int w, int h) = { GRIDLIST(GRID_FN) };
-static const int NUM_GRID_TYPES = sizeof(grid_fns) / sizeof(grid_fns[0]);
+static grid_type grid_types[] = { GRIDLIST(GRID_TYPE) };
+#define NUM_GRID_TYPES (sizeof(grid_types) / sizeof(grid_types[0]))
+static const struct {
+ int amin, omin;
+ char *aerr, *oerr;
+} grid_size_limits[] = { GRIDLIST(GRID_SIZES) };
/* Generates a (dynamically allocated) new grid, according to the
* type and size requested in params. Does nothing if the grid is already
- * generated. The allocated grid is owned by the params object, and will be
- * freed in free_params(). */
-static void params_generate_grid(game_params *params)
+ * generated. */
+static grid *loopy_generate_grid(const game_params *params,
+ const char *grid_desc)
{
- if (!params->game_grid) {
- params->game_grid = grid_fns[params->type](params->w, params->h);
- }
+ return grid_new(grid_types[params->type], params->w, params->h, grid_desc);
}
/* ----------------------------------------------------------------------
((field) &= ~(1<<(bit)), TRUE) : FALSE)
#define CLUE2CHAR(c) \
- ((c < 0) ? ' ' : c + '0')
+ ((c < 0) ? ' ' : c < 10 ? c + '0' : c - 10 + 'A')
/* ----------------------------------------------------------------------
* General struct manipulation and other straightforward code
*/
-static game_state *dup_game(game_state *state)
+static game_state *dup_game(const game_state *state)
{
game_state *ret = snew(game_state);
ret->lines = snewn(state->game_grid->num_edges, char);
memcpy(ret->lines, state->lines, state->game_grid->num_edges);
+ ret->line_errors = snewn(state->game_grid->num_edges, unsigned char);
+ memcpy(ret->line_errors, state->line_errors, state->game_grid->num_edges);
+ ret->exactly_one_loop = state->exactly_one_loop;
+
ret->grid_type = state->grid_type;
return ret;
}
grid_free(state->game_grid);
sfree(state->clues);
sfree(state->lines);
+ sfree(state->line_errors);
sfree(state);
}
}
-static solver_state *new_solver_state(game_state *state, int diff) {
+static solver_state *new_solver_state(const game_state *state, int diff) {
int i;
int num_dots = state->game_grid->num_dots;
int num_faces = state->game_grid->num_faces;
ret->state = dup_game(state);
ret->solver_status = SOLVER_INCOMPLETE;
+ ret->diff = diff;
ret->dotdsf = snew_dsf(num_dots);
ret->looplen = snewn(num_dots, int);
memset(ret->face_no_count, 0, num_faces);
if (diff < DIFF_NORMAL) {
- ret->normal = NULL;
+ ret->dlines = NULL;
} else {
- ret->normal = snew(normal_mode_state);
- ret->normal->dlines = snewn(2*num_edges, char);
- memset(ret->normal->dlines, 0, 2*num_edges);
+ ret->dlines = snewn(2*num_edges, char);
+ memset(ret->dlines, 0, 2*num_edges);
}
if (diff < DIFF_HARD) {
- ret->hard = NULL;
+ ret->linedsf = NULL;
} else {
- ret->hard = snew(hard_mode_state);
- ret->hard->linedsf = snew_dsf(state->game_grid->num_edges);
+ ret->linedsf = snew_dsf(state->game_grid->num_edges);
}
return ret;
sfree(sstate->face_yes_count);
sfree(sstate->face_no_count);
- if (sstate->normal) {
- sfree(sstate->normal->dlines);
- sfree(sstate->normal);
- }
-
- if (sstate->hard) {
- sfree(sstate->hard->linedsf);
- sfree(sstate->hard);
- }
+ /* OK, because sfree(NULL) is a no-op */
+ sfree(sstate->dlines);
+ sfree(sstate->linedsf);
sfree(sstate);
}
ret->state = state = dup_game(sstate->state);
ret->solver_status = sstate->solver_status;
+ ret->diff = sstate->diff;
ret->dotdsf = snewn(num_dots, int);
ret->looplen = snewn(num_dots, int);
ret->face_no_count = snewn(num_faces, char);
memcpy(ret->face_no_count, sstate->face_no_count, num_faces);
- if (sstate->normal) {
- ret->normal = snew(normal_mode_state);
- ret->normal->dlines = snewn(2*num_edges, char);
- memcpy(ret->normal->dlines, sstate->normal->dlines,
+ if (sstate->dlines) {
+ ret->dlines = snewn(2*num_edges, char);
+ memcpy(ret->dlines, sstate->dlines,
2*num_edges);
} else {
- ret->normal = NULL;
+ ret->dlines = NULL;
}
- if (sstate->hard) {
- ret->hard = snew(hard_mode_state);
- ret->hard->linedsf = snewn(num_edges, int);
- memcpy(ret->hard->linedsf, sstate->hard->linedsf,
+ if (sstate->linedsf) {
+ ret->linedsf = snewn(num_edges, int);
+ memcpy(ret->linedsf, sstate->linedsf,
num_edges * sizeof(int));
} else {
- ret->hard = NULL;
+ ret->linedsf = NULL;
}
return ret;
ret->diff = DIFF_EASY;
ret->type = 0;
- ret->game_grid = NULL;
-
return ret;
}
-static game_params *dup_params(game_params *params)
+static game_params *dup_params(const game_params *params)
{
game_params *ret = snew(game_params);
*ret = *params; /* structure copy */
- if (ret->game_grid) {
- ret->game_grid->refcount++;
- }
return ret;
}
static const game_params presets[] = {
- { 7, 7, DIFF_EASY, 0, NULL },
- { 10, 10, DIFF_EASY, 0, NULL },
- { 7, 7, DIFF_NORMAL, 0, NULL },
- { 10, 10, DIFF_NORMAL, 0, NULL },
- { 7, 7, DIFF_HARD, 0, NULL },
- { 10, 10, DIFF_HARD, 0, NULL },
- { 10, 10, DIFF_HARD, 1, NULL },
- { 12, 10, DIFF_HARD, 2, NULL },
- { 7, 7, DIFF_HARD, 3, NULL },
- { 9, 9, DIFF_HARD, 4, NULL },
- { 5, 4, DIFF_HARD, 5, NULL },
- { 7, 7, DIFF_HARD, 6, NULL },
- { 5, 5, DIFF_HARD, 7, NULL },
+#ifdef SMALL_SCREEN
+ { 7, 7, DIFF_EASY, 0 },
+ { 7, 7, DIFF_NORMAL, 0 },
+ { 7, 7, DIFF_HARD, 0 },
+ { 7, 7, DIFF_HARD, 1 },
+ { 7, 7, DIFF_HARD, 2 },
+ { 5, 5, DIFF_HARD, 3 },
+ { 7, 7, DIFF_HARD, 4 },
+ { 5, 4, DIFF_HARD, 5 },
+ { 5, 5, DIFF_HARD, 6 },
+ { 5, 5, DIFF_HARD, 7 },
+ { 3, 3, DIFF_HARD, 8 },
+ { 3, 3, DIFF_HARD, 9 },
+ { 3, 3, DIFF_HARD, 10 },
+ { 6, 6, DIFF_HARD, 11 },
+ { 6, 6, DIFF_HARD, 12 },
+#else
+ { 7, 7, DIFF_EASY, 0 },
+ { 10, 10, DIFF_EASY, 0 },
+ { 7, 7, DIFF_NORMAL, 0 },
+ { 10, 10, DIFF_NORMAL, 0 },
+ { 7, 7, DIFF_HARD, 0 },
+ { 10, 10, DIFF_HARD, 0 },
+ { 10, 10, DIFF_HARD, 1 },
+ { 12, 10, DIFF_HARD, 2 },
+ { 7, 7, DIFF_HARD, 3 },
+ { 9, 9, DIFF_HARD, 4 },
+ { 5, 4, DIFF_HARD, 5 },
+ { 7, 7, DIFF_HARD, 6 },
+ { 5, 5, DIFF_HARD, 7 },
+ { 5, 5, DIFF_HARD, 8 },
+ { 5, 4, DIFF_HARD, 9 },
+ { 5, 4, DIFF_HARD, 10 },
+ { 10, 10, DIFF_HARD, 11 },
+ { 10, 10, DIFF_HARD, 12 }
+#endif
};
static int game_fetch_preset(int i, char **name, game_params **params)
static void free_params(game_params *params)
{
- if (params->game_grid) {
- grid_free(params->game_grid);
- }
sfree(params);
}
static void decode_params(game_params *params, char const *string)
{
- if (params->game_grid) {
- grid_free(params->game_grid);
- params->game_grid = NULL;
- }
params->h = params->w = atoi(string);
params->diff = DIFF_EASY;
while (*string && isdigit((unsigned char)*string)) string++;
}
}
-static char *encode_params(game_params *params, int full)
+static char *encode_params(const game_params *params, int full)
{
char str[80];
sprintf(str, "%dx%dt%d", params->w, params->h, params->type);
return dupstr(str);
}
-static config_item *game_configure(game_params *params)
+static config_item *game_configure(const game_params *params)
{
config_item *ret;
char buf[80];
return ret;
}
-static game_params *custom_params(config_item *cfg)
+static game_params *custom_params(const config_item *cfg)
{
game_params *ret = snew(game_params);
ret->type = cfg[2].ival;
ret->diff = cfg[3].ival;
- ret->game_grid = NULL;
return ret;
}
-static char *validate_params(game_params *params, int full)
+static char *validate_params(const game_params *params, int full)
{
- if (params->w < 3 || params->h < 3)
- return "Width and height must both be at least 3";
if (params->type < 0 || params->type >= NUM_GRID_TYPES)
return "Illegal grid type";
+ if (params->w < grid_size_limits[params->type].amin ||
+ params->h < grid_size_limits[params->type].amin)
+ return grid_size_limits[params->type].aerr;
+ if (params->w < grid_size_limits[params->type].omin &&
+ params->h < grid_size_limits[params->type].omin)
+ return grid_size_limits[params->type].oerr;
/*
* This shouldn't be able to happen at all, since decode_params
return retval;
}
+#define GRID_DESC_SEP '_'
+
+/* Splits up a (optional) grid_desc from the game desc. Returns the
+ * grid_desc (which needs freeing) and updates the desc pointer to
+ * start of real desc, or returns NULL if no desc. */
+static char *extract_grid_desc(const char **desc)
+{
+ char *sep = strchr(*desc, GRID_DESC_SEP), *gd;
+ int gd_len;
+
+ if (!sep) return NULL;
+
+ gd_len = sep - (*desc);
+ gd = snewn(gd_len+1, char);
+ memcpy(gd, *desc, gd_len);
+ gd[gd_len] = '\0';
+
+ *desc = sep+1;
+
+ return gd;
+}
+
/* We require that the params pass the test in validate_params and that the
* description fills the entire game area */
-static char *validate_desc(game_params *params, char *desc)
+static char *validate_desc(const game_params *params, const char *desc)
{
int count = 0;
grid *g;
- params_generate_grid(params);
- g = params->game_grid;
+ char *grid_desc, *ret;
+
+ /* It's pretty inefficient to do this just for validation. All we need to
+ * know is the precise number of faces. */
+ grid_desc = extract_grid_desc(&desc);
+ ret = grid_validate_desc(grid_types[params->type], params->w, params->h, grid_desc);
+ if (ret) return ret;
+
+ g = loopy_generate_grid(params, grid_desc);
+ if (grid_desc) sfree(grid_desc);
for (; *desc; ++desc) {
- if (*desc >= '0' && *desc <= '9') {
+ if ((*desc >= '0' && *desc <= '9') || (*desc >= 'A' && *desc <= 'Z')) {
count++;
continue;
}
if (count > g->num_faces)
return "Description too long for board size";
+ grid_free(g);
+
return NULL;
}
return ret;
}
-static game_ui *new_ui(game_state *state)
+static game_ui *new_ui(const game_state *state)
{
return NULL;
}
{
}
-static char *encode_ui(game_ui *ui)
+static char *encode_ui(const game_ui *ui)
{
return NULL;
}
-static void decode_ui(game_ui *ui, char *encoding)
+static void decode_ui(game_ui *ui, const char *encoding)
{
}
-static void game_changed_state(game_ui *ui, game_state *oldstate,
- game_state *newstate)
+static void game_changed_state(game_ui *ui, const game_state *oldstate,
+ const game_state *newstate)
{
}
-static void game_compute_size(game_params *params, int tilesize,
+static void game_compute_size(const game_params *params, int tilesize,
int *x, int *y)
{
- grid *g;
- params_generate_grid(params);
- g = params->game_grid;
- int grid_width = g->highest_x - g->lowest_x;
- int grid_height = g->highest_y - g->lowest_y;
+ int grid_width, grid_height, rendered_width, rendered_height;
+ int g_tilesize;
+
+ grid_compute_size(grid_types[params->type], params->w, params->h,
+ &g_tilesize, &grid_width, &grid_height);
+
/* multiply first to minimise rounding error on integer division */
- int rendered_width = grid_width * tilesize / g->tilesize;
- int rendered_height = grid_height * tilesize / g->tilesize;
+ rendered_width = grid_width * tilesize / g_tilesize;
+ rendered_height = grid_height * tilesize / g_tilesize;
*x = rendered_width + 2 * BORDER(tilesize) + 1;
*y = rendered_height + 2 * BORDER(tilesize) + 1;
}
static void game_set_size(drawing *dr, game_drawstate *ds,
- game_params *params, int tilesize)
+ const game_params *params, int tilesize)
{
ds->tilesize = tilesize;
}
static float *game_colours(frontend *fe, int *ncolours)
{
- float *ret = snewn(4 * NCOLOURS, float);
+ float *ret = snewn(3 * NCOLOURS, float);
frontend_default_colour(fe, &ret[COL_BACKGROUND * 3]);
ret[COL_FOREGROUND * 3 + 1] = 0.0F;
ret[COL_FOREGROUND * 3 + 2] = 0.0F;
- ret[COL_LINEUNKNOWN * 3 + 0] = 0.8F;
- ret[COL_LINEUNKNOWN * 3 + 1] = 0.8F;
+ /*
+ * We want COL_LINEUNKNOWN to be a yellow which is a bit darker
+ * than the background. (I previously set it to 0.8,0.8,0, but
+ * found that this went badly with the 0.8,0.8,0.8 favoured as a
+ * background by the Java frontend.)
+ */
+ ret[COL_LINEUNKNOWN * 3 + 0] = ret[COL_BACKGROUND * 3 + 0] * 0.9F;
+ ret[COL_LINEUNKNOWN * 3 + 1] = ret[COL_BACKGROUND * 3 + 1] * 0.9F;
ret[COL_LINEUNKNOWN * 3 + 2] = 0.0F;
ret[COL_HIGHLIGHT * 3 + 0] = 1.0F;
ret[COL_SATISFIED * 3 + 1] = 0.0F;
ret[COL_SATISFIED * 3 + 2] = 0.0F;
+ /* We want the faint lines to be a bit darker than the background.
+ * Except if the background is pretty dark already; then it ought to be a
+ * bit lighter. Oy vey.
+ */
+ ret[COL_FAINT * 3 + 0] = ret[COL_BACKGROUND * 3 + 0] * 0.9F;
+ ret[COL_FAINT * 3 + 1] = ret[COL_BACKGROUND * 3 + 1] * 0.9F;
+ ret[COL_FAINT * 3 + 2] = ret[COL_BACKGROUND * 3 + 2] * 0.9F;
+
*ncolours = NCOLOURS;
return ret;
}
-static game_drawstate *game_new_drawstate(drawing *dr, game_state *state)
+static game_drawstate *game_new_drawstate(drawing *dr, const game_state *state)
{
struct game_drawstate *ds = snew(struct game_drawstate);
int num_faces = state->game_grid->num_faces;
int num_edges = state->game_grid->num_edges;
+ int i;
ds->tilesize = 0;
ds->started = 0;
ds->lines = snewn(num_edges, char);
ds->clue_error = snewn(num_faces, char);
ds->clue_satisfied = snewn(num_faces, char);
+ ds->textx = snewn(num_faces, int);
+ ds->texty = snewn(num_faces, int);
ds->flashing = 0;
memset(ds->lines, LINE_UNKNOWN, num_edges);
memset(ds->clue_error, 0, num_faces);
memset(ds->clue_satisfied, 0, num_faces);
+ for (i = 0; i < num_faces; i++)
+ ds->textx[i] = ds->texty[i] = -1;
return ds;
}
static void game_free_drawstate(drawing *dr, game_drawstate *ds)
{
+ sfree(ds->textx);
+ sfree(ds->texty);
sfree(ds->clue_error);
sfree(ds->clue_satisfied);
sfree(ds->lines);
sfree(ds);
}
-static int game_timing_state(game_state *state, game_ui *ui)
+static int game_timing_state(const game_state *state, game_ui *ui)
{
return TRUE;
}
-static float game_anim_length(game_state *oldstate, game_state *newstate,
- int dir, game_ui *ui)
+static float game_anim_length(const game_state *oldstate,
+ const game_state *newstate, int dir, game_ui *ui)
{
return 0.0F;
}
-static int game_can_format_as_text_now(game_params *params)
+static int game_can_format_as_text_now(const game_params *params)
{
if (params->type != 0)
return FALSE;
return TRUE;
}
-static char *game_text_format(game_state *state)
+static char *game_text_format(const game_state *state)
{
int w, h, W, H;
int x, y, i;
/* Fill in clues */
for (i = 0; i < g->num_faces; i++) {
+ int x1, x2, y1, y2;
+
f = g->faces + i;
assert(f->order == 4);
/* Cell coordinates, from (0,0) to (w-1,h-1) */
- int x1 = (f->dots[0]->x - g->lowest_x) / cell_size;
- int x2 = (f->dots[2]->x - g->lowest_x) / cell_size;
- int y1 = (f->dots[0]->y - g->lowest_y) / cell_size;
- int y2 = (f->dots[2]->y - g->lowest_y) / cell_size;
+ x1 = (f->dots[0]->x - g->lowest_x) / cell_size;
+ x2 = (f->dots[2]->x - g->lowest_x) / cell_size;
+ y1 = (f->dots[0]->y - g->lowest_y) / cell_size;
+ y2 = (f->dots[2]->y - g->lowest_y) / cell_size;
/* Midpoint, in canvas coordinates */
x = x1 + x2;
y = y1 + y2;
assert(i < sstate->state->game_grid->num_edges);
assert(j < sstate->state->game_grid->num_edges);
- i = edsf_canonify(sstate->hard->linedsf, i, &inv_tmp);
+ i = edsf_canonify(sstate->linedsf, i, &inv_tmp);
inverse ^= inv_tmp;
- j = edsf_canonify(sstate->hard->linedsf, j, &inv_tmp);
+ j = edsf_canonify(sstate->linedsf, j, &inv_tmp);
inverse ^= inv_tmp;
- edsf_merge(sstate->hard->linedsf, i, j, inverse);
+ edsf_merge(sstate->linedsf, i, j, inverse);
#ifdef SHOW_WORKING
if (i != j) {
* Loop generation and clue removal
*/
-/* We're going to store a list of current candidate faces for lighting.
- * Each face gets a 'score', which tells us how adding that face right
- * now would affect the length of the solution loop. We're trying to
- * maximise that quantity so will bias our random selection of faces to
- * light towards those with high scores */
-struct face {
- int score;
- unsigned long random;
- grid_face *f;
-};
-
-static int get_face_cmpfn(void *v1, void *v2)
-{
- struct face *f1 = v1;
- struct face *f2 = v2;
- /* These grid_face pointers always point into the same list of
- * 'grid_face's, so it's valid to subtract them. */
- return f1->f - f2->f;
-}
-
-static int face_sort_cmpfn(void *v1, void *v2)
-{
- struct face *f1 = v1;
- struct face *f2 = v2;
- int r;
-
- r = f2->score - f1->score;
- if (r) {
- return r;
- }
-
- if (f1->random < f2->random)
- return -1;
- else if (f1->random > f2->random)
- return 1;
-
- /*
- * It's _just_ possible that two faces might have been given
- * the same random value. In that situation, fall back to
- * comparing based on the positions within the grid's face-list.
- * This introduces a tiny directional bias, but not a significant one.
- */
- return get_face_cmpfn(f1, f2);
-}
-
-enum { FACE_LIT, FACE_UNLIT };
-
-/* face should be of type grid_face* here. */
-#define FACE_LIT_STATE(face) \
- ( (face) == NULL ? FACE_UNLIT : \
- board[(face) - g->faces] )
-
-/* 'board' is an array of these enums, indicating which faces are
- * currently lit. Returns whether it's legal to light up the
- * given face. */
-static int can_light_face(grid *g, char* board, int face_index)
-{
- int i, j;
- grid_face *test_face = g->faces + face_index;
- grid_face *starting_face, *current_face;
- int transitions;
- int current_state, s;
- int found_lit_neighbour = FALSE;
- assert(board[face_index] == FACE_UNLIT);
-
- /* Can only consider a face for lighting if it's adjacent to an
- * already lit face. */
- for (i = 0; i < test_face->order; i++) {
- grid_edge *e = test_face->edges[i];
- grid_face *f = (e->face1 == test_face) ? e->face2 : e->face1;
- if (FACE_LIT_STATE(f) == FACE_LIT) {
- found_lit_neighbour = TRUE;
- break;
- }
- }
- if (!found_lit_neighbour)
- return FALSE;
-
- /* Need to avoid creating a loop of lit faces around some unlit faces.
- * Also need to avoid meeting another lit face at a corner, with
- * unlit faces in between. Here's a simple test that (I believe) takes
- * care of both these conditions:
- *
- * Take the circular path formed by this face's edges, and inflate it
- * slightly outwards. Imagine walking around this path and consider
- * the faces that you visit in sequence. This will include all faces
- * touching the given face, either along an edge or just at a corner.
- * Count the number of LIT/UNLIT transitions you encounter, as you walk
- * along the complete loop. This will obviously turn out to be an even
- * number.
- * If 0, we're either in a completely unlit zone, or this face is a hole
- * in a completely lit zone. If the former, we would create a brand new
- * island by lighting this face. And the latter ought to be impossible -
- * it would mean there's already a lit loop, so something went wrong
- * earlier.
- * If 4 or greater, there are too many separate lit regions touching this
- * face, and lighting it up would create a loop or a corner-violation.
- * The only allowed case is when the count is exactly 2. */
-
- /* i points to a dot around the test face.
- * j points to a face around the i^th dot.
- * The current face will always be:
- * test_face->dots[i]->faces[j]
- * We assume dots go clockwise around the test face,
- * and faces go clockwise around dots. */
- i = j = 0;
- starting_face = test_face->dots[0]->faces[0];
- if (starting_face == test_face) {
- j = 1;
- starting_face = test_face->dots[0]->faces[1];
- }
- current_face = starting_face;
- transitions = 0;
- current_state = FACE_LIT_STATE(current_face);
-
- do {
- /* Advance to next face.
- * Need to loop here because it might take several goes to
- * find it. */
- while (TRUE) {
- j++;
- if (j == test_face->dots[i]->order)
- j = 0;
-
- if (test_face->dots[i]->faces[j] == test_face) {
- /* Advance to next dot round test_face, then
- * find current_face around new dot
- * and advance to the next face clockwise */
- i++;
- if (i == test_face->order)
- i = 0;
- for (j = 0; j < test_face->dots[i]->order; j++) {
- if (test_face->dots[i]->faces[j] == current_face)
- break;
- }
- /* Must actually find current_face around new dot,
- * or else something's wrong with the grid. */
- assert(j != test_face->dots[i]->order);
- /* Found, so advance to next face and try again */
- } else {
- break;
- }
- }
- /* (i,j) are now advanced to next face */
- current_face = test_face->dots[i]->faces[j];
- s = FACE_LIT_STATE(current_face);
- if (s != current_state) {
- ++transitions;
- current_state = s;
- if (transitions > 2)
- return FALSE; /* no point in continuing */
- }
- } while (current_face != starting_face);
-
- return (transitions == 2) ? TRUE : FALSE;
-}
-
-/* The 'score' of a face reflects its current desirability for selection
- * as the next face to light. We want to encourage moving into uncharted
- * areas so we give scores according to how many of the face's neighbours
- * are currently unlit. */
-static int face_score(grid *g, char *board, grid_face *face)
-{
- /* Simple formula: score = neighbours unlit - neighbours lit */
- int lit_count = 0, unlit_count = 0;
- int i;
- grid_face *f;
- grid_edge *e;
- for (i = 0; i < face->order; i++) {
- e = face->edges[i];
- f = (e->face1 == face) ? e->face2 : e->face1;
- if (FACE_LIT_STATE(f) == FACE_LIT)
- ++lit_count;
- else
- ++unlit_count;
- }
- return unlit_count - lit_count;
-}
-
-/* Generate a new complete set of clues for the given game_state. */
static void add_full_clues(game_state *state, random_state *rs)
{
signed char *clues = state->clues;
- char *board;
grid *g = state->game_grid;
- int i, j, c;
- int num_faces = g->num_faces;
- int first_time = TRUE;
-
- struct face *face, *tmpface;
- struct face face_pos;
-
- /* These will contain exactly the same information, sorted into different
- * orders */
- tree234 *lightable_faces_sorted, *lightable_faces_gettable;
-
-#define IS_LIGHTING_CANDIDATE(i) \
- (board[i] == FACE_UNLIT && \
- can_light_face(g, board, i))
-
- board = snewn(num_faces, char);
-
- /* Make a board */
- memset(board, FACE_UNLIT, num_faces);
-
- /* We need a way of favouring faces that will increase our loopiness.
- * We do this by maintaining a list of all candidate faces sorted by
- * their score and choose randomly from that with appropriate skew.
- * In order to avoid consistently biasing towards particular faces, we
- * need the sort order _within_ each group of scores to be completely
- * random. But it would be abusing the hospitality of the tree234 data
- * structure if our comparison function were nondeterministic :-). So with
- * each face we associate a random number that does not change during a
- * particular run of the generator, and use that as a secondary sort key.
- * Yes, this means we will be biased towards particular random faces in
- * any one run but that doesn't actually matter. */
-
- lightable_faces_sorted = newtree234(face_sort_cmpfn);
- lightable_faces_gettable = newtree234(get_face_cmpfn);
-#define ADD_FACE(f) \
- do { \
- struct face *x = add234(lightable_faces_sorted, f); \
- assert(x == f); \
- x = add234(lightable_faces_gettable, f); \
- assert(x == f); \
- } while (0)
-
-#define REMOVE_FACE(f) \
- do { \
- struct face *x = del234(lightable_faces_sorted, f); \
- assert(x); \
- x = del234(lightable_faces_gettable, f); \
- assert(x); \
- } while (0)
-
- /* Light faces one at a time until the board is interesting enough */
- while (TRUE)
- {
- if (first_time) {
- first_time = FALSE;
- /* lightable_faces_xxx are empty, so start the process by
- * lighting up the middle face. These tree234s should
- * remain empty, consistent with what would happen if
- * first_time were FALSE. */
- board[g->middle_face - g->faces] = FACE_LIT;
- face = snew(struct face);
- face->f = g->middle_face;
- /* No need to initialise any more of 'face' here, no other fields
- * are used in this case. */
- } else {
- /* We have count234(lightable_faces_gettable) possibilities, and in
- * lightable_faces_sorted they are sorted with the most desirable
- * first. */
- c = count234(lightable_faces_sorted);
- if (c == 0)
- break;
- assert(c == count234(lightable_faces_gettable));
-
- /* Check that the best face available is any good */
- face = (struct face *)index234(lightable_faces_sorted, 0);
- assert(face);
-
- /*
- * The situation for a general grid is slightly different from
- * a square grid. Decreasing the perimeter should be allowed
- * sometimes (think about creating a hexagon of lit triangles,
- * for example). For if it were _never_ done, then the user would
- * be able to illicitly deduce certain things. So we do it
- * sometimes but not always.
- */
- if (face->score <= 0 && random_upto(rs, 2) == 0) {
- break;
- }
-
- assert(face->f); /* not the infinite face */
- assert(FACE_LIT_STATE(face->f) == FACE_UNLIT);
-
- /* Update data structures */
- /* Light up the face and remove it from the lists */
- board[face->f - g->faces] = FACE_LIT;
- REMOVE_FACE(face);
- }
-
- /* The face we've just lit up potentially affects the lightability
- * of any neighbouring faces (touching at a corner or edge). So the
- * search needs to be conducted around all faces touching the one
- * we've just lit. Iterate over its corners, then over each corner's
- * faces. */
- for (i = 0; i < face->f->order; i++) {
- grid_dot *d = face->f->dots[i];
- for (j = 0; j < d->order; j++) {
- grid_face *f2 = d->faces[j];
- if (f2 == NULL)
- continue;
- if (f2 == face->f)
- continue;
- face_pos.f = f2;
- tmpface = find234(lightable_faces_gettable, &face_pos, NULL);
- if (tmpface) {
- assert(tmpface->f == face_pos.f);
- assert(FACE_LIT_STATE(tmpface->f) == FACE_UNLIT);
- REMOVE_FACE(tmpface);
- } else {
- tmpface = snew(struct face);
- tmpface->f = face_pos.f;
- tmpface->random = random_bits(rs, 31);
- }
- tmpface->score = face_score(g, board, tmpface->f);
-
- if (IS_LIGHTING_CANDIDATE(tmpface->f - g->faces)) {
- ADD_FACE(tmpface);
- } else {
- sfree(tmpface);
- }
- }
- }
- sfree(face);
- }
+ char *board = snewn(g->num_faces, char);
+ int i;
- /* Clean up */
- while ((face = delpos234(lightable_faces_gettable, 0)) != NULL)
- sfree(face);
- freetree234(lightable_faces_gettable);
- freetree234(lightable_faces_sorted);
+ generate_loop(g, board, rs, NULL, NULL);
/* Fill out all the clues by initialising to 0, then iterating over
* all edges and incrementing each clue as we find edges that border
- * between LIT/UNLIT faces */
- memset(clues, 0, num_faces);
+ * between BLACK/WHITE faces. While we're at it, we verify that the
+ * algorithm does work, and there aren't any GREY faces still there. */
+ memset(clues, 0, g->num_faces);
for (i = 0; i < g->num_edges; i++) {
grid_edge *e = g->edges + i;
grid_face *f1 = e->face1;
grid_face *f2 = e->face2;
- if (FACE_LIT_STATE(f1) != FACE_LIT_STATE(f2)) {
+ enum face_colour c1 = FACE_COLOUR(f1);
+ enum face_colour c2 = FACE_COLOUR(f2);
+ assert(c1 != FACE_GREY);
+ assert(c2 != FACE_GREY);
+ if (c1 != c2) {
if (f1) clues[f1 - g->faces]++;
if (f2) clues[f2 - g->faces]++;
}
}
-
sfree(board);
}
solver_state *sstate_new;
solver_state *sstate = new_solver_state((game_state *)state, diff);
- sstate_new = solve_game_rec(sstate, diff);
+ sstate_new = solve_game_rec(sstate);
assert(sstate_new->solver_status != SOLVER_MISTAKE);
ret = (sstate_new->solver_status == SOLVER_SOLVED);
}
-static char *new_game_desc(game_params *params, random_state *rs,
+static char *new_game_desc(const game_params *params, random_state *rs,
char **aux, int interactive)
{
/* solution and description both use run-length encoding in obvious ways */
- char *retval;
+ char *retval, *game_desc, *grid_desc;
grid *g;
game_state *state = snew(game_state);
game_state *state_new;
- params_generate_grid(params);
- state->game_grid = g = params->game_grid;
- g->refcount++;
+
+ grid_desc = grid_new_desc(grid_types[params->type], params->w, params->h, rs);
+ state->game_grid = g = loopy_generate_grid(params, grid_desc);
+
state->clues = snewn(g->num_faces, signed char);
state->lines = snewn(g->num_edges, char);
+ state->line_errors = snewn(g->num_edges, unsigned char);
+ state->exactly_one_loop = FALSE;
state->grid_type = params->type;
newboard_please:
memset(state->lines, LINE_UNKNOWN, g->num_edges);
+ memset(state->line_errors, 0, g->num_edges);
state->solved = state->cheated = FALSE;
goto newboard_please;
}
- retval = state_to_text(state);
+ game_desc = state_to_text(state);
free_game(state);
+ if (grid_desc) {
+ retval = snewn(strlen(grid_desc) + 1 + strlen(game_desc) + 1, char);
+ sprintf(retval, "%s%c%s", grid_desc, (int)GRID_DESC_SEP, game_desc);
+ sfree(grid_desc);
+ sfree(game_desc);
+ } else {
+ retval = game_desc;
+ }
+
assert(!validate_desc(params, retval));
return retval;
}
-static game_state *new_game(midend *me, game_params *params, char *desc)
+static game_state *new_game(midend *me, const game_params *params,
+ const char *desc)
{
int i;
game_state *state = snew(game_state);
int empties_to_make = 0;
- int n;
- const char *dp = desc;
+ int n,n2;
+ const char *dp;
+ char *grid_desc;
grid *g;
- params_generate_grid(params);
- state->game_grid = g = params->game_grid;
- g->refcount++;
- int num_faces = g->num_faces;
- int num_edges = g->num_edges;
+ int num_faces, num_edges;
+
+ grid_desc = extract_grid_desc(&desc);
+ state->game_grid = g = loopy_generate_grid(params, grid_desc);
+ if (grid_desc) sfree(grid_desc);
+
+ dp = desc;
+
+ num_faces = g->num_faces;
+ num_edges = g->num_edges;
state->clues = snewn(num_faces, signed char);
state->lines = snewn(num_edges, char);
+ state->line_errors = snewn(num_edges, unsigned char);
+ state->exactly_one_loop = FALSE;
state->solved = state->cheated = FALSE;
assert(*dp);
n = *dp - '0';
+ n2 = *dp - 'A' + 10;
if (n >= 0 && n < 10) {
state->clues[i] = n;
+ } else if (n2 >= 10 && n2 < 36) {
+ state->clues[i] = n2;
} else {
n = *dp - 'a' + 1;
assert(n > 0);
}
memset(state->lines, LINE_UNKNOWN, num_edges);
-
+ memset(state->line_errors, 0, num_edges);
return state;
}
-enum { LOOP_NONE=0, LOOP_SOLN, LOOP_NOT_SOLN };
+/* Calculates the line_errors data, and checks if the current state is a
+ * solution */
+static int check_completion(game_state *state)
+{
+ grid *g = state->game_grid;
+ int i, ret;
+ int *dsf, *component_state;
+ int nsilly, nloop, npath, largest_comp, largest_size, total_pathsize;
+ enum { COMP_NONE, COMP_LOOP, COMP_PATH, COMP_SILLY, COMP_EMPTY };
+
+ memset(state->line_errors, 0, g->num_edges);
+
+ /*
+ * Find loops in the grid, and determine whether the puzzle is
+ * solved.
+ *
+ * Loopy is a bit more complicated than most puzzles that care
+ * about loop detection. In most of them, loops are simply
+ * _forbidden_; so the obviously right way to do
+ * error-highlighting during play is to light up a graph edge red
+ * iff it is part of a loop, which is exactly what the centralised
+ * findloop.c makes easy.
+ *
+ * But Loopy is unusual in that you're _supposed_ to be making a
+ * loop - and yet _some_ loops are not the right loop. So we need
+ * to be more discriminating, by identifying loops one by one and
+ * then thinking about which ones to highlight, and so findloop.c
+ * isn't quite the right tool for the job in this case.
+ *
+ * Worse still, consider situations in which the grid contains a
+ * loop and also some non-loop edges: there are some cases like
+ * this in which the user's intuitive expectation would be to
+ * highlight the loop (if you're only about half way through the
+ * puzzle and have accidentally made a little loop in some corner
+ * of the grid), and others in which they'd be more likely to
+ * expect you to highlight the non-loop edges (if you've just
+ * closed off a whole loop that you thought was the entire
+ * solution, but forgot some disconnected edges in a corner
+ * somewhere). So while it's easy enough to check whether the
+ * solution is _right_, highlighting the wrong parts is a tricky
+ * problem for this puzzle!
+ *
+ * I'd quite like, in some situations, to identify the largest
+ * loop among the player's YES edges, and then light up everything
+ * other than that. But finding the longest cycle in a graph is an
+ * NP-complete problem (because, in particular, it must return a
+ * Hamilton cycle if one exists).
+ *
+ * However, I think we can make the problem tractable by
+ * exercising the Puzzles principle that it isn't absolutely
+ * necessary to highlight _all_ errors: the key point is that by
+ * the time the user has filled in the whole grid, they should
+ * either have seen a completion flash, or have _some_ error
+ * highlight showing them why the solution isn't right. So in
+ * principle it would be *just about* good enough to highlight
+ * just one error in the whole grid, if there was really no better
+ * way. But we'd like to highlight as many errors as possible.
+ *
+ * In this case, I think the simple approach is to make use of the
+ * fact that no vertex may have degree > 2, and that's really
+ * simple to detect. So the plan goes like this:
+ *
+ * - Form the dsf of connected components of the graph vertices.
+ *
+ * - Highlight an error at any vertex with degree > 2. (It so
+ * happens that we do this by lighting up all the edges
+ * incident to that vertex, but that's an output detail.)
+ *
+ * - Any component that contains such a vertex is now excluded
+ * from further consideration, because it already has a
+ * highlight.
+ *
+ * - The remaining components have no vertex with degree > 2, and
+ * hence they all consist of either a simple loop, or a simple
+ * path with two endpoints.
+ *
+ * - For these purposes, group together all the paths and imagine
+ * them to be a single component (because in most normal
+ * situations the player will gradually build up the solution
+ * _not_ all in one connected segment, but as lots of separate
+ * little path pieces that gradually connect to each other).
+ *
+ * - After doing that, if there is exactly one (sensible)
+ * component - be it a collection of paths or a loop - then
+ * highlight no further edge errors. (The former case is normal
+ * during play, and the latter is a potentially solved puzzle.)
+ *
+ * - Otherwise, find the largest of the sensible components,
+ * leave that one unhighlighted, and light the rest up in red.
+ */
+
+ dsf = snew_dsf(g->num_dots);
+
+ /* Build the dsf. */
+ for (i = 0; i < g->num_edges; i++) {
+ if (state->lines[i] == LINE_YES) {
+ grid_edge *e = g->edges + i;
+ int d1 = e->dot1 - g->dots, d2 = e->dot2 - g->dots;
+ dsf_merge(dsf, d1, d2);
+ }
+ }
+
+ /* Initialise a state variable for each connected component. */
+ component_state = snewn(g->num_dots, int);
+ for (i = 0; i < g->num_dots; i++) {
+ if (dsf_canonify(dsf, i) == i)
+ component_state[i] = COMP_LOOP;
+ else
+ component_state[i] = COMP_NONE;
+ }
+
+ /* Check for dots with degree > 3. Here we also spot dots of
+ * degree 1 in which the user has marked all the non-edges as
+ * LINE_NO, because those are also clear vertex-level errors, so
+ * we give them the same treatment of excluding their connected
+ * component from the subsequent loop analysis. */
+ for (i = 0; i < g->num_dots; i++) {
+ int comp = dsf_canonify(dsf, i);
+ int yes = dot_order(state, i, LINE_YES);
+ int unknown = dot_order(state, i, LINE_UNKNOWN);
+ if ((yes == 1 && unknown == 0) || (yes >= 3)) {
+ /* violation, so mark all YES edges as errors */
+ grid_dot *d = g->dots + i;
+ int j;
+ for (j = 0; j < d->order; j++) {
+ int e = d->edges[j] - g->edges;
+ if (state->lines[e] == LINE_YES)
+ state->line_errors[e] = TRUE;
+ }
+ /* And mark this component as not worthy of further
+ * consideration. */
+ component_state[comp] = COMP_SILLY;
+
+ } else if (yes == 0) {
+ /* A completely isolated dot must also be excluded it from
+ * the subsequent loop highlighting pass, but we tag it
+ * with a different enum value to avoid it counting
+ * towards the components that inhibit returning a win
+ * status. */
+ component_state[comp] = COMP_EMPTY;
+ } else if (yes == 1) {
+ /* A dot with degree 1 that didn't fall into the 'clearly
+ * erroneous' case above indicates that this connected
+ * component will be a path rather than a loop - unless
+ * something worse elsewhere in the component has
+ * classified it as silly. */
+ if (component_state[comp] != COMP_SILLY)
+ component_state[comp] = COMP_PATH;
+ }
+ }
+
+ /* Count up the components. Also, find the largest sensible
+ * component. (Tie-breaking condition is derived from the order of
+ * vertices in the grid data structure, which is fairly arbitrary
+ * but at least stays stable throughout the game.) */
+ nsilly = nloop = npath = 0;
+ total_pathsize = 0;
+ largest_comp = largest_size = -1;
+ for (i = 0; i < g->num_dots; i++) {
+ if (component_state[i] == COMP_SILLY) {
+ nsilly++;
+ } else if (component_state[i] == COMP_PATH) {
+ total_pathsize += dsf_size(dsf, i);
+ npath = 1;
+ } else if (component_state[i] == COMP_LOOP) {
+ int this_size;
+
+ nloop++;
+
+ if ((this_size = dsf_size(dsf, i)) > largest_size) {
+ largest_comp = i;
+ largest_size = this_size;
+ }
+ }
+ }
+ if (largest_size < total_pathsize) {
+ largest_comp = -1; /* means the paths */
+ largest_size = total_pathsize;
+ }
+
+ if (nloop > 0 && nloop + npath > 1) {
+ /*
+ * If there are at least two sensible components including at
+ * least one loop, highlight all edges in every sensible
+ * component that is not the largest one.
+ */
+ for (i = 0; i < g->num_edges; i++) {
+ if (state->lines[i] == LINE_YES) {
+ grid_edge *e = g->edges + i;
+ int d1 = e->dot1 - g->dots; /* either endpoint is good enough */
+ int comp = dsf_canonify(dsf, d1);
+ if ((component_state[comp] == COMP_PATH &&
+ -1 != largest_comp) ||
+ (component_state[comp] == COMP_LOOP &&
+ comp != largest_comp))
+ state->line_errors[i] = TRUE;
+ }
+ }
+ }
+
+ if (nloop == 1 && npath == 0 && nsilly == 0) {
+ /*
+ * If there is exactly one component and it is a loop, then
+ * the puzzle is potentially complete, so check the clues.
+ */
+ ret = TRUE;
+
+ for (i = 0; i < g->num_faces; i++) {
+ int c = state->clues[i];
+ if (c >= 0 && face_order(state, i, LINE_YES) != c) {
+ ret = FALSE;
+ break;
+ }
+ }
+
+ /*
+ * Also, whether or not the puzzle is actually complete, set
+ * the flag that says this game_state has exactly one loop and
+ * nothing else, which will be used to vary the semantics of
+ * clue highlighting at display time.
+ */
+ state->exactly_one_loop = TRUE;
+ } else {
+ ret = FALSE;
+ state->exactly_one_loop = FALSE;
+ }
+
+ sfree(component_state);
+ sfree(dsf);
+
+ return ret;
+}
/* ----------------------------------------------------------------------
* Solver logic
* Easy Mode
* Just implement the rules of the game.
*
- * Normal Mode
+ * Normal and Tricky Modes
* For each (adjacent) pair of lines through each dot we store a bit for
* whether at least one of them is on and whether at most one is on. (If we
* know both or neither is on that's already stored more directly.)
continue;
/* Found opposite UNKNOWNS and they're next to each other */
opp_dline_index = dline_index_from_dot(g, d, opp);
- return set_atleastone(sstate->normal->dlines, opp_dline_index);
+ return set_atleastone(sstate->dlines, opp_dline_index);
}
return FALSE;
}
continue;
/* Found two UNKNOWNS */
- can1 = edsf_canonify(sstate->hard->linedsf, line1_index, &inv1);
- can2 = edsf_canonify(sstate->hard->linedsf, line2_index, &inv2);
+ can1 = edsf_canonify(sstate->linedsf, line1_index, &inv1);
+ can2 = edsf_canonify(sstate->linedsf, line2_index, &inv2);
if (can1 == can2 && inv1 == inv2) {
solver_set_line(sstate, line1_index, line_new);
solver_set_line(sstate, line2_index, line_new);
{
game_state *state = sstate->state;
int diff = DIFF_MAX;
- int *linedsf = sstate->hard->linedsf;
+ int *linedsf = sstate->linedsf;
if (unknown_count == 2) {
/* Lines are known alike/opposite, depending on inv. */
* Answer: first all squares then all dots.
*/
-static int easy_mode_deductions(solver_state *sstate)
+static int trivial_deductions(solver_state *sstate)
{
int i, current_yes, current_no;
game_state *state = sstate->state;
if (state->clues[i] < 0)
continue;
+ /*
+ * This code checks whether the numeric clue on a face is so
+ * large as to permit all its remaining LINE_UNKNOWNs to be
+ * filled in as LINE_YES, or alternatively so small as to
+ * permit them all to be filled in as LINE_NO.
+ */
+
if (state->clues[i] < current_yes) {
sstate->solver_status = SOLVER_MISTAKE;
return DIFF_EASY;
sstate->face_solved[i] = TRUE;
continue;
}
+
+ if (f->order - state->clues[i] == current_no + 1 &&
+ f->order - current_yes - current_no > 2) {
+ /*
+ * One small refinement to the above: we also look for any
+ * adjacent pair of LINE_UNKNOWNs around the face with
+ * some LINE_YES incident on it from elsewhere. If we find
+ * one, then we know that pair of LINE_UNKNOWNs can't
+ * _both_ be LINE_YES, and hence that pushes us one line
+ * closer to being able to determine all the rest.
+ */
+ int j, k, e1, e2, e, d;
+
+ for (j = 0; j < f->order; j++) {
+ e1 = f->edges[j] - g->edges;
+ e2 = f->edges[j+1 < f->order ? j+1 : 0] - g->edges;
+
+ if (g->edges[e1].dot1 == g->edges[e2].dot1 ||
+ g->edges[e1].dot1 == g->edges[e2].dot2) {
+ d = g->edges[e1].dot1 - g->dots;
+ } else {
+ assert(g->edges[e1].dot2 == g->edges[e2].dot1 ||
+ g->edges[e1].dot2 == g->edges[e2].dot2);
+ d = g->edges[e1].dot2 - g->dots;
+ }
+
+ if (state->lines[e1] == LINE_UNKNOWN &&
+ state->lines[e2] == LINE_UNKNOWN) {
+ for (k = 0; k < g->dots[d].order; k++) {
+ int e = g->dots[d].edges[k] - g->edges;
+ if (state->lines[e] == LINE_YES)
+ goto found; /* multi-level break */
+ }
+ }
+ }
+ continue;
+
+ found:
+ /*
+ * If we get here, we've found such a pair of edges, and
+ * they're e1 and e2.
+ */
+ for (j = 0; j < f->order; j++) {
+ e = f->edges[j] - g->edges;
+ if (state->lines[e] == LINE_UNKNOWN && e != e1 && e != e2) {
+ int r = solver_set_line(sstate, e, LINE_YES);
+ assert(r);
+ diff = min(diff, DIFF_EASY);
+ }
+ }
+ }
}
check_caches(sstate);
return diff;
}
-static int normal_mode_deductions(solver_state *sstate)
+static int dline_deductions(solver_state *sstate)
{
game_state *state = sstate->state;
grid *g = state->game_grid;
- char *dlines = sstate->normal->dlines;
+ char *dlines = sstate->dlines;
int i;
int diff = DIFF_MAX;
* on that. We check this with an assertion, in case someone decides to
* make a grid which has larger faces than this. Note, this algorithm
* could get quite expensive if there are many large faces. */
-#define MAX_FACE_SIZE 8
+#define MAX_FACE_SIZE 12
for (i = 0; i < g->num_faces; i++) {
int maxs[MAX_FACE_SIZE][MAX_FACE_SIZE];
diff = min(diff, DIFF_EASY);
}
- /* Now see if we can make dline deduction for edges{j,j+1} */
- e = f->edges[k];
- if (state->lines[e - g->edges] != LINE_UNKNOWN)
- /* Only worth doing this for an UNKNOWN,UNKNOWN pair.
- * Dlines where one of the edges is known, are handled in the
- * dot-deductions */
- continue;
-
- dline_index = dline_index_from_face(g, f, k);
- k++;
- if (k >= N) k = 0;
-
- /* minimum YESs in the complement of this dline */
- if (mins[k][j] > clue - 2) {
- /* Adding 2 YESs would break the clue */
- if (set_atmostone(dlines, dline_index))
- diff = min(diff, DIFF_NORMAL);
- }
- /* maximum YESs in the complement of this dline */
- if (maxs[k][j] < clue) {
- /* Adding 2 NOs would mean not enough YESs */
- if (set_atleastone(dlines, dline_index))
- diff = min(diff, DIFF_NORMAL);
+ /* More advanced deduction that allows propagation along diagonal
+ * chains of faces connected by dots, for example, 3-2-...-2-3
+ * in square grids. */
+ if (sstate->diff >= DIFF_TRICKY) {
+ /* Now see if we can make dline deduction for edges{j,j+1} */
+ e = f->edges[k];
+ if (state->lines[e - g->edges] != LINE_UNKNOWN)
+ /* Only worth doing this for an UNKNOWN,UNKNOWN pair.
+ * Dlines where one of the edges is known, are handled in the
+ * dot-deductions */
+ continue;
+
+ dline_index = dline_index_from_face(g, f, k);
+ k++;
+ if (k >= N) k = 0;
+
+ /* minimum YESs in the complement of this dline */
+ if (mins[k][j] > clue - 2) {
+ /* Adding 2 YESs would break the clue */
+ if (set_atmostone(dlines, dline_index))
+ diff = min(diff, DIFF_NORMAL);
+ }
+ /* maximum YESs in the complement of this dline */
+ if (maxs[k][j] < clue) {
+ /* Adding 2 NOs would mean not enough YESs */
+ if (set_atleastone(dlines, dline_index))
+ diff = min(diff, DIFF_NORMAL);
+ }
}
}
}
}
}
- /* If we have atleastone set for this dline, infer
- * atmostone for each "opposite" dline (that is, each
- * dline without edges in common with this one).
- * Again, this test is only worth doing if both these
- * lines are UNKNOWN. For if one of these lines were YES,
- * the (yes == 1) test above would kick in instead. */
- if (is_atleastone(dlines, dline_index)) {
- int opp;
- for (opp = 0; opp < N; opp++) {
- int opp_dline_index;
- if (opp == j || opp == j+1 || opp == j-1)
- continue;
- if (j == 0 && opp == N-1)
- continue;
- if (j == N-1 && opp == 0)
- continue;
- opp_dline_index = dline_index_from_dot(g, d, opp);
- if (set_atmostone(dlines, opp_dline_index))
- diff = min(diff, DIFF_NORMAL);
- }
-
- if (yes == 0 && is_atmostone(dlines, dline_index)) {
- /* This dline has *exactly* one YES and there are no
- * other YESs. This allows more deductions. */
- if (unknown == 3) {
- /* Third unknown must be YES */
- for (opp = 0; opp < N; opp++) {
- int opp_index;
- if (opp == j || opp == k)
- continue;
- opp_index = d->edges[opp] - g->edges;
- if (state->lines[opp_index] == LINE_UNKNOWN) {
- solver_set_line(sstate, opp_index, LINE_YES);
- diff = min(diff, DIFF_EASY);
+ /* More advanced deduction that allows propagation along diagonal
+ * chains of faces connected by dots, for example: 3-2-...-2-3
+ * in square grids. */
+ if (sstate->diff >= DIFF_TRICKY) {
+ /* If we have atleastone set for this dline, infer
+ * atmostone for each "opposite" dline (that is, each
+ * dline without edges in common with this one).
+ * Again, this test is only worth doing if both these
+ * lines are UNKNOWN. For if one of these lines were YES,
+ * the (yes == 1) test above would kick in instead. */
+ if (is_atleastone(dlines, dline_index)) {
+ int opp;
+ for (opp = 0; opp < N; opp++) {
+ int opp_dline_index;
+ if (opp == j || opp == j+1 || opp == j-1)
+ continue;
+ if (j == 0 && opp == N-1)
+ continue;
+ if (j == N-1 && opp == 0)
+ continue;
+ opp_dline_index = dline_index_from_dot(g, d, opp);
+ if (set_atmostone(dlines, opp_dline_index))
+ diff = min(diff, DIFF_NORMAL);
+ }
+ if (yes == 0 && is_atmostone(dlines, dline_index)) {
+ /* This dline has *exactly* one YES and there are no
+ * other YESs. This allows more deductions. */
+ if (unknown == 3) {
+ /* Third unknown must be YES */
+ for (opp = 0; opp < N; opp++) {
+ int opp_index;
+ if (opp == j || opp == k)
+ continue;
+ opp_index = d->edges[opp] - g->edges;
+ if (state->lines[opp_index] == LINE_UNKNOWN) {
+ solver_set_line(sstate, opp_index,
+ LINE_YES);
+ diff = min(diff, DIFF_EASY);
+ }
}
+ } else if (unknown == 4) {
+ /* Exactly one of opposite UNKNOWNS is YES. We've
+ * already set atmostone, so set atleastone as
+ * well.
+ */
+ if (dline_set_opp_atleastone(sstate, d, j))
+ diff = min(diff, DIFF_NORMAL);
}
- } else if (unknown == 4) {
- /* Exactly one of opposite UNKNOWNS is YES. We've
- * already set atmostone, so set atleastone as well.
- */
- if (dline_set_opp_atleastone(sstate, d, j))
- diff = min(diff, DIFF_NORMAL);
}
}
}
return diff;
}
-static int hard_mode_deductions(solver_state *sstate)
+static int linedsf_deductions(solver_state *sstate)
{
game_state *state = sstate->state;
grid *g = state->game_grid;
- char *dlines = sstate->normal->dlines;
+ char *dlines = sstate->dlines;
int i;
int diff = DIFF_MAX;
int diff_tmp;
if (state->lines[line2_index] != LINE_UNKNOWN)
continue;
/* Infer dline flags from linedsf */
- can1 = edsf_canonify(sstate->hard->linedsf, line1_index, &inv1);
- can2 = edsf_canonify(sstate->hard->linedsf, line2_index, &inv2);
+ can1 = edsf_canonify(sstate->linedsf, line1_index, &inv1);
+ can2 = edsf_canonify(sstate->linedsf, line2_index, &inv2);
if (can1 == can2 && inv1 != inv2) {
/* These are opposites, so set dline atmostone/atleastone */
if (set_atmostone(dlines, dline_index))
for (i = 0; i < g->num_edges; i++) {
int can, inv;
enum line_state s;
- can = edsf_canonify(sstate->hard->linedsf, i, &inv);
+ can = edsf_canonify(sstate->linedsf, i, &inv);
if (can == i)
continue;
s = sstate->state->lines[can];
/* This will return a dynamically allocated solver_state containing the (more)
* solved grid */
-static solver_state *solve_game_rec(const solver_state *sstate_start,
- int diff)
-{
- solver_state *sstate, *sstate_saved;
- int solver_progress;
- game_state *state;
-
- /* Indicates which solver we should call next. This is a sensible starting
- * point */
- int current_solver = DIFF_EASY, next_solver;
+static solver_state *solve_game_rec(const solver_state *sstate_start)
+{
+ solver_state *sstate;
+
+ /* Index of the solver we should call next. */
+ int i = 0;
+
+ /* As a speed-optimisation, we avoid re-running solvers that we know
+ * won't make any progress. This happens when a high-difficulty
+ * solver makes a deduction that can only help other high-difficulty
+ * solvers.
+ * For example: if a new 'dline' flag is set by dline_deductions, the
+ * trivial_deductions solver cannot do anything with this information.
+ * If we've already run the trivial_deductions solver (because it's
+ * earlier in the list), there's no point running it again.
+ *
+ * Therefore: if a solver is earlier in the list than "threshold_index",
+ * we don't bother running it if it's difficulty level is less than
+ * "threshold_diff".
+ */
+ int threshold_diff = 0;
+ int threshold_index = 0;
+
sstate = dup_solver_state(sstate_start);
- /* Cache the values of some variables for readability */
- state = sstate->state;
-
- sstate_saved = NULL;
-
- solver_progress = FALSE;
-
check_caches(sstate);
- do {
+ while (i < NUM_SOLVERS) {
if (sstate->solver_status == SOLVER_MISTAKE)
return sstate;
-
- next_solver = solver_fns[current_solver](sstate);
-
- if (next_solver == DIFF_MAX) {
- if (current_solver < diff && current_solver + 1 < DIFF_MAX) {
- /* Try next beefier solver */
- next_solver = current_solver + 1;
- } else {
- next_solver = loop_deductions(sstate);
- }
- }
-
if (sstate->solver_status == SOLVER_SOLVED ||
sstate->solver_status == SOLVER_AMBIGUOUS) {
-/* fprintf(stderr, "Solver completed\n"); */
+ /* solver finished */
break;
}
- /* Once we've looped over all permitted solvers then the loop
- * deductions without making any progress, we'll exit this while loop */
- current_solver = next_solver;
- } while (current_solver < DIFF_MAX);
+ if ((solver_diffs[i] >= threshold_diff || i >= threshold_index)
+ && solver_diffs[i] <= sstate->diff) {
+ /* current_solver is eligible, so use it */
+ int next_diff = solver_fns[i](sstate);
+ if (next_diff != DIFF_MAX) {
+ /* solver made progress, so use new thresholds and
+ * start again at top of list. */
+ threshold_diff = next_diff;
+ threshold_index = i;
+ i = 0;
+ continue;
+ }
+ }
+ /* current_solver is ineligible, or failed to make progress, so
+ * go to the next solver in the list */
+ i++;
+ }
if (sstate->solver_status == SOLVER_SOLVED ||
sstate->solver_status == SOLVER_AMBIGUOUS) {
return sstate;
}
-static char *solve_game(game_state *state, game_state *currstate,
- char *aux, char **error)
+static char *solve_game(const game_state *state, const game_state *currstate,
+ const char *aux, char **error)
{
char *soln = NULL;
solver_state *sstate, *new_sstate;
sstate = new_solver_state(state, DIFF_MAX);
- new_sstate = solve_game_rec(sstate, DIFF_MAX);
+ new_sstate = solve_game_rec(sstate);
if (new_sstate->solver_status == SOLVER_SOLVED) {
soln = encode_solve_move(new_sstate->state);
* Drawing and mouse-handling
*/
-static char *interpret_move(game_state *state, game_ui *ui, game_drawstate *ds,
+static char *interpret_move(const game_state *state, game_ui *ui,
+ const game_drawstate *ds,
int x, int y, int button)
{
grid *g = state->game_grid;
button_char = 'y';
break;
case LINE_YES:
+#ifdef STYLUS_BASED
+ button_char = 'n';
+ break;
+#endif
case LINE_NO:
button_char = 'u';
break;
button_char = 'n';
break;
case LINE_NO:
+#ifdef STYLUS_BASED
+ button_char = 'y';
+ break;
+#endif
case LINE_YES:
button_char = 'u';
break;
return ret;
}
-static game_state *execute_move(game_state *state, char *move)
+static game_state *execute_move(const game_state *state, const char *move)
{
int i;
game_state *newstate = dup_game(state);
- grid *g = state->game_grid;
if (move[0] == 'S') {
move++;
while (*move) {
i = atoi(move);
+ if (i < 0 || i >= newstate->game_grid->num_edges)
+ goto fail;
move += strspn(move, "1234567890");
switch (*(move++)) {
case 'y':
/*
* Check for completion.
*/
- for (i = 0; i < g->num_edges; i++) {
- if (newstate->lines[i] == LINE_YES)
- break;
- }
- if (i < g->num_edges) {
- int looplen, count;
- grid_edge *start_edge = g->edges + i;
- grid_edge *e = start_edge;
- grid_dot *d = e->dot1;
- /*
- * We've found an edge i. Follow it round
- * to see if it's part of a loop.
- */
- looplen = 0;
- while (1) {
- int j;
- int order = dot_order(newstate, d - g->dots, LINE_YES);
- if (order != 2)
- goto completion_check_done;
-
- /* Find other edge around this dot */
- for (j = 0; j < d->order; j++) {
- grid_edge *e2 = d->edges[j];
- if (e2 != e && newstate->lines[e2 - g->edges] == LINE_YES)
- break;
- }
- assert(j != d->order); /* dot_order guarantees success */
-
- e = d->edges[j];
- d = (e->dot1 == d) ? e->dot2 : e->dot1;
- looplen++;
-
- if (e == start_edge)
- break;
- }
-
- /*
- * We've traced our way round a loop, and we know how many
- * line segments were involved. Count _all_ the line
- * segments in the grid, to see if the loop includes them
- * all.
- */
- count = 0;
- for (i = 0; i < g->num_edges; i++) {
- if (newstate->lines[i] == LINE_YES)
- count++;
- }
- assert(count >= looplen);
- if (count != looplen)
- goto completion_check_done;
-
- /*
- * The grid contains one closed loop and nothing else.
- * Check that all the clues are satisfied.
- */
- for (i = 0; i < g->num_faces; i++) {
- int c = newstate->clues[i];
- if (c >= 0) {
- if (face_order(newstate, i, LINE_YES) != c) {
- goto completion_check_done;
- }
- }
- }
-
- /*
- * Completed!
- */
+ if (check_completion(newstate))
newstate->solved = TRUE;
- }
- completion_check_done:
return newstate;
fail:
/* Returns (into x,y) position of centre of face for rendering the text clue.
*/
static void face_text_pos(const game_drawstate *ds, const grid *g,
- const grid_face *f, int *x, int *y)
+ grid_face *f, int *xret, int *yret)
{
- int i;
+ int faceindex = f - g->faces;
+
+ /*
+ * Return the cached position for this face, if we've already
+ * worked it out.
+ */
+ if (ds->textx[faceindex] >= 0) {
+ *xret = ds->textx[faceindex];
+ *yret = ds->texty[faceindex];
+ return;
+ }
- /* Simplest solution is the centroid. Might not work in some cases. */
+ /*
+ * Otherwise, use the incentre computed by grid.c and convert it
+ * to screen coordinates.
+ */
+ grid_find_incentre(f);
+ grid_to_screen(ds, g, f->ix, f->iy,
+ &ds->textx[faceindex], &ds->texty[faceindex]);
+
+ *xret = ds->textx[faceindex];
+ *yret = ds->texty[faceindex];
+}
- /* Another algorithm to look into:
- * Find the midpoints of the sides, find the bounding-box,
- * then take the centre of that. */
+static void face_text_bbox(game_drawstate *ds, grid *g, grid_face *f,
+ int *x, int *y, int *w, int *h)
+{
+ int xx, yy;
+ face_text_pos(ds, g, f, &xx, &yy);
- /* Best solution probably involves incentres (inscribed circles) */
+ /* There seems to be a certain amount of trial-and-error involved
+ * in working out the correct bounding-box for the text. */
- int sx = 0, sy = 0; /* sums */
- for (i = 0; i < f->order; i++) {
- grid_dot *d = f->dots[i];
- sx += d->x;
- sy += d->y;
+ *x = xx - ds->tilesize/4 - 1;
+ *y = yy - ds->tilesize/4 - 3;
+ *w = ds->tilesize/2 + 2;
+ *h = ds->tilesize/2 + 5;
+}
+
+static void game_redraw_clue(drawing *dr, game_drawstate *ds,
+ const game_state *state, int i)
+{
+ grid *g = state->game_grid;
+ grid_face *f = g->faces + i;
+ int x, y;
+ char c[20];
+
+ sprintf(c, "%d", state->clues[i]);
+
+ face_text_pos(ds, g, f, &x, &y);
+ draw_text(dr, x, y,
+ FONT_VARIABLE, ds->tilesize/2,
+ ALIGN_VCENTRE | ALIGN_HCENTRE,
+ ds->clue_error[i] ? COL_MISTAKE :
+ ds->clue_satisfied[i] ? COL_SATISFIED : COL_FOREGROUND, c);
+}
+
+static void edge_bbox(game_drawstate *ds, grid *g, grid_edge *e,
+ int *x, int *y, int *w, int *h)
+{
+ int x1 = e->dot1->x;
+ int y1 = e->dot1->y;
+ int x2 = e->dot2->x;
+ int y2 = e->dot2->y;
+ int xmin, xmax, ymin, ymax;
+
+ grid_to_screen(ds, g, x1, y1, &x1, &y1);
+ grid_to_screen(ds, g, x2, y2, &x2, &y2);
+ /* Allow extra margin for dots, and thickness of lines */
+ xmin = min(x1, x2) - 2;
+ xmax = max(x1, x2) + 2;
+ ymin = min(y1, y2) - 2;
+ ymax = max(y1, y2) + 2;
+
+ *x = xmin;
+ *y = ymin;
+ *w = xmax - xmin + 1;
+ *h = ymax - ymin + 1;
+}
+
+static void dot_bbox(game_drawstate *ds, grid *g, grid_dot *d,
+ int *x, int *y, int *w, int *h)
+{
+ int x1, y1;
+
+ grid_to_screen(ds, g, d->x, d->y, &x1, &y1);
+
+ *x = x1 - 2;
+ *y = y1 - 2;
+ *w = 5;
+ *h = 5;
+}
+
+static const int loopy_line_redraw_phases[] = {
+ COL_FAINT, COL_LINEUNKNOWN, COL_FOREGROUND, COL_HIGHLIGHT, COL_MISTAKE
+};
+#define NPHASES lenof(loopy_line_redraw_phases)
+
+static void game_redraw_line(drawing *dr, game_drawstate *ds,
+ const game_state *state, int i, int phase)
+{
+ grid *g = state->game_grid;
+ grid_edge *e = g->edges + i;
+ int x1, x2, y1, y2;
+ int line_colour;
+
+ if (state->line_errors[i])
+ line_colour = COL_MISTAKE;
+ else if (state->lines[i] == LINE_UNKNOWN)
+ line_colour = COL_LINEUNKNOWN;
+ else if (state->lines[i] == LINE_NO)
+ line_colour = COL_FAINT;
+ else if (ds->flashing)
+ line_colour = COL_HIGHLIGHT;
+ else
+ line_colour = COL_FOREGROUND;
+ if (line_colour != loopy_line_redraw_phases[phase])
+ return;
+
+ /* Convert from grid to screen coordinates */
+ grid_to_screen(ds, g, e->dot1->x, e->dot1->y, &x1, &y1);
+ grid_to_screen(ds, g, e->dot2->x, e->dot2->y, &x2, &y2);
+
+ if (line_colour == COL_FAINT) {
+ static int draw_faint_lines = -1;
+ if (draw_faint_lines < 0) {
+ char *env = getenv("LOOPY_FAINT_LINES");
+ draw_faint_lines = (!env || (env[0] == 'y' ||
+ env[0] == 'Y'));
+ }
+ if (draw_faint_lines)
+ draw_line(dr, x1, y1, x2, y2, line_colour);
+ } else {
+ draw_thick_line(dr, 3.0,
+ x1 + 0.5, y1 + 0.5,
+ x2 + 0.5, y2 + 0.5,
+ line_colour);
+ }
+}
+
+static void game_redraw_dot(drawing *dr, game_drawstate *ds,
+ const game_state *state, int i)
+{
+ grid *g = state->game_grid;
+ grid_dot *d = g->dots + i;
+ int x, y;
+
+ grid_to_screen(ds, g, d->x, d->y, &x, &y);
+ draw_circle(dr, x, y, 2, COL_FOREGROUND, COL_FOREGROUND);
+}
+
+static int boxes_intersect(int x0, int y0, int w0, int h0,
+ int x1, int y1, int w1, int h1)
+{
+ /*
+ * Two intervals intersect iff neither is wholly on one side of
+ * the other. Two boxes intersect iff their horizontal and
+ * vertical intervals both intersect.
+ */
+ return (x0 < x1+w1 && x1 < x0+w0 && y0 < y1+h1 && y1 < y0+h0);
+}
+
+static void game_redraw_in_rect(drawing *dr, game_drawstate *ds,
+ const game_state *state,
+ int x, int y, int w, int h)
+{
+ grid *g = state->game_grid;
+ int i, phase;
+ int bx, by, bw, bh;
+
+ clip(dr, x, y, w, h);
+ draw_rect(dr, x, y, w, h, COL_BACKGROUND);
+
+ for (i = 0; i < g->num_faces; i++) {
+ if (state->clues[i] >= 0) {
+ face_text_bbox(ds, g, &g->faces[i], &bx, &by, &bw, &bh);
+ if (boxes_intersect(x, y, w, h, bx, by, bw, bh))
+ game_redraw_clue(dr, ds, state, i);
+ }
+ }
+ for (phase = 0; phase < NPHASES; phase++) {
+ for (i = 0; i < g->num_edges; i++) {
+ edge_bbox(ds, g, &g->edges[i], &bx, &by, &bw, &bh);
+ if (boxes_intersect(x, y, w, h, bx, by, bw, bh))
+ game_redraw_line(dr, ds, state, i, phase);
+ }
+ }
+ for (i = 0; i < g->num_dots; i++) {
+ dot_bbox(ds, g, &g->dots[i], &bx, &by, &bw, &bh);
+ if (boxes_intersect(x, y, w, h, bx, by, bw, bh))
+ game_redraw_dot(dr, ds, state, i);
}
- sx /= f->order;
- sy /= f->order;
- /* convert to screen coordinates */
- grid_to_screen(ds, g, sx, sy, x, y);
+ unclip(dr);
+ draw_update(dr, x, y, w, h);
}
-static void game_redraw(drawing *dr, game_drawstate *ds, game_state *oldstate,
- game_state *state, int dir, game_ui *ui,
+static void game_redraw(drawing *dr, game_drawstate *ds,
+ const game_state *oldstate, const game_state *state,
+ int dir, const game_ui *ui,
float animtime, float flashtime)
{
+#define REDRAW_OBJECTS_LIMIT 16 /* Somewhat arbitrary tradeoff */
+
grid *g = state->game_grid;
int border = BORDER(ds->tilesize);
- int i, n;
- char c[2];
- int line_colour, flash_changed;
- int clue_mistake;
- int clue_satisfied;
+ int i;
+ int flash_changed;
+ int redraw_everything = FALSE;
+
+ int edges[REDRAW_OBJECTS_LIMIT], nedges = 0;
+ int faces[REDRAW_OBJECTS_LIMIT], nfaces = 0;
+
+ /* Redrawing is somewhat involved.
+ *
+ * An update can theoretically affect an arbitrary number of edges
+ * (consider, for example, completing or breaking a cycle which doesn't
+ * satisfy all the clues -- we'll switch many edges between error and
+ * normal states). On the other hand, redrawing the whole grid takes a
+ * while, making the game feel sluggish, and many updates are actually
+ * quite well localized.
+ *
+ * This redraw algorithm attempts to cope with both situations gracefully
+ * and correctly. For localized changes, we set a clip rectangle, fill
+ * it with background, and then redraw (a plausible but conservative
+ * guess at) the objects which intersect the rectangle; if several
+ * objects need redrawing, we'll do them individually. However, if lots
+ * of objects are affected, we'll just redraw everything.
+ *
+ * The reason for all of this is that it's just not safe to do the redraw
+ * piecemeal. If you try to draw an antialiased diagonal line over
+ * itself, you get a slightly thicker antialiased diagonal line, which
+ * looks rather ugly after a while.
+ *
+ * So, we take two passes over the grid. The first attempts to work out
+ * what needs doing, and the second actually does it.
+ */
if (!ds->started) {
+ redraw_everything = TRUE;
/*
- * The initial contents of the window are not guaranteed and
- * can vary with front ends. To be on the safe side, all games
- * should start by drawing a big background-colour rectangle
- * covering the whole window.
+ * But we must still go through the upcoming loops, so that we
+ * set up stuff in ds correctly for the initial redraw.
*/
- int grid_width = g->highest_x - g->lowest_x;
- int grid_height = g->highest_y - g->lowest_y;
- int w = grid_width * ds->tilesize / g->tilesize;
- int h = grid_height * ds->tilesize / g->tilesize;
- draw_rect(dr, 0, 0, w + 2 * border, h + 2 * border, COL_BACKGROUND);
+ }
- /* Draw clues */
- for (i = 0; i < g->num_faces; i++) {
- c[0] = CLUE2CHAR(state->clues[i]);
- c[1] = '\0';
- int x, y;
- grid_face *f = g->faces + i;
- face_text_pos(ds, g, f, &x, &y);
- draw_text(dr, x, y, FONT_VARIABLE, ds->tilesize/2,
- ALIGN_VCENTRE | ALIGN_HCENTRE, COL_FOREGROUND, c);
+ /* First, trundle through the faces. */
+ for (i = 0; i < g->num_faces; i++) {
+ grid_face *f = g->faces + i;
+ int sides = f->order;
+ int yes_order, no_order;
+ int clue_mistake;
+ int clue_satisfied;
+ int n = state->clues[i];
+ if (n < 0)
+ continue;
+
+ yes_order = face_order(state, i, LINE_YES);
+ if (state->exactly_one_loop) {
+ /*
+ * Special case: if the set of LINE_YES edges in the grid
+ * consists of exactly one loop and nothing else, then we
+ * switch to treating LINE_UNKNOWN the same as LINE_NO for
+ * purposes of clue checking.
+ *
+ * This is because some people like to play Loopy without
+ * using the right-click, i.e. never setting anything to
+ * LINE_NO. Without this special case, if a person playing
+ * in that style fills in what they think is a correct
+ * solution loop but in fact it has an underfilled clue,
+ * then we will display no victory flash and also no error
+ * highlight explaining why not. With this special case,
+ * we light up underfilled clues at the instant the loop
+ * is closed. (Of course, *overfilled* clues are fine
+ * either way.)
+ *
+ * (It might still be considered unfortunate that we can't
+ * warn this style of player any earlier, if they make a
+ * mistake very near the beginning which doesn't show up
+ * until they close the last edge of the loop. One other
+ * thing we _could_ do here is to treat any LINE_UNKNOWN
+ * as LINE_NO if either of its endpoints has yes-degree 2,
+ * reflecting the fact that setting that line to YES would
+ * be an obvious error. But I don't think even that could
+ * catch _all_ clue errors in a timely manner; I think
+ * there are some that won't be displayed until the loop
+ * is filled in, even so, and there's no way to avoid that
+ * with complete reliability except to switch to being a
+ * player who sets things to LINE_NO.)
+ */
+ no_order = sides - yes_order;
+ } else {
+ no_order = face_order(state, i, LINE_NO);
+ }
+
+ clue_mistake = (yes_order > n || no_order > (sides-n));
+ clue_satisfied = (yes_order == n && no_order == (sides-n));
+
+ if (clue_mistake != ds->clue_error[i] ||
+ clue_satisfied != ds->clue_satisfied[i]) {
+ ds->clue_error[i] = clue_mistake;
+ ds->clue_satisfied[i] = clue_satisfied;
+ if (nfaces == REDRAW_OBJECTS_LIMIT)
+ redraw_everything = TRUE;
+ else
+ faces[nfaces++] = i;
}
- draw_update(dr, 0, 0, w + 2 * border, h + 2 * border);
}
+ /* Work out what the flash state needs to be. */
if (flashtime > 0 &&
(flashtime <= FLASH_TIME/3 ||
flashtime >= FLASH_TIME*2/3)) {
ds->flashing = FALSE;
}
- /* Some platforms may perform anti-aliasing, which may prevent clean
- * repainting of lines when the colour is changed.
- * If a line needs to be over-drawn in a different colour, erase a
- * bounding-box around the line, then flag all nearby objects for redraw.
- */
- if (ds->started) {
- const char redraw_flag = 1<<7;
- for (i = 0; i < g->num_edges; i++) {
- /* If we're changing state, AND
- * the previous state was a coloured line */
- if ((state->lines[i] != (ds->lines[i] & ~redraw_flag)) &&
- ((ds->lines[i] & ~redraw_flag) != LINE_NO)) {
- grid_edge *e = g->edges + i;
- int x1 = e->dot1->x;
- int y1 = e->dot1->y;
- int x2 = e->dot2->x;
- int y2 = e->dot2->y;
- int xmin, xmax, ymin, ymax;
- int j;
- grid_to_screen(ds, g, x1, y1, &x1, &y1);
- grid_to_screen(ds, g, x2, y2, &x2, &y2);
- /* Allow extra margin for dots, and thickness of lines */
- xmin = min(x1, x2) - 2;
- xmax = max(x1, x2) + 2;
- ymin = min(y1, y2) - 2;
- ymax = max(y1, y2) + 2;
- /* For testing, I find it helpful to change COL_BACKGROUND
- * to COL_SATISFIED here. */
- draw_rect(dr, xmin, ymin, xmax - xmin + 1, ymax - ymin + 1,
- COL_BACKGROUND);
- draw_update(dr, xmin, ymin, xmax - xmin + 1, ymax - ymin + 1);
-
- /* Mark nearby lines for redraw */
- for (j = 0; j < e->dot1->order; j++)
- ds->lines[e->dot1->edges[j] - g->edges] |= redraw_flag;
- for (j = 0; j < e->dot2->order; j++)
- ds->lines[e->dot2->edges[j] - g->edges] |= redraw_flag;
- /* Mark nearby clues for redraw. Use a value that is
- * neither TRUE nor FALSE for this. */
- if (e->face1)
- ds->clue_error[e->face1 - g->faces] = 2;
- if (e->face2)
- ds->clue_error[e->face2 - g->faces] = 2;
- }
+ /* Now, trundle through the edges. */
+ for (i = 0; i < g->num_edges; i++) {
+ char new_ds =
+ state->line_errors[i] ? DS_LINE_ERROR : state->lines[i];
+ if (new_ds != ds->lines[i] ||
+ (flash_changed && state->lines[i] == LINE_YES)) {
+ ds->lines[i] = new_ds;
+ if (nedges == REDRAW_OBJECTS_LIMIT)
+ redraw_everything = TRUE;
+ else
+ edges[nedges++] = i;
}
}
- /* Redraw clue colours if necessary */
- for (i = 0; i < g->num_faces; i++) {
- grid_face *f = g->faces + i;
- int sides = f->order;
- int j;
- n = state->clues[i];
- if (n < 0)
- continue;
-
- c[0] = CLUE2CHAR(n);
- c[1] = '\0';
-
- clue_mistake = (face_order(state, i, LINE_YES) > n ||
- face_order(state, i, LINE_NO ) > (sides-n));
-
- clue_satisfied = (face_order(state, i, LINE_YES) == n &&
- face_order(state, i, LINE_NO ) == (sides-n));
-
- if (clue_mistake != ds->clue_error[i]
- || clue_satisfied != ds->clue_satisfied[i]) {
- int x, y;
- face_text_pos(ds, g, f, &x, &y);
- /* There seems to be a certain amount of trial-and-error
- * involved in working out the correct bounding-box for
- * the text. */
- draw_rect(dr, x - ds->tilesize/4 - 1, y - ds->tilesize/4 - 3,
- ds->tilesize/2 + 2, ds->tilesize/2 + 5,
- COL_BACKGROUND);
- draw_text(dr, x, y,
- FONT_VARIABLE, ds->tilesize/2,
- ALIGN_VCENTRE | ALIGN_HCENTRE,
- clue_mistake ? COL_MISTAKE :
- clue_satisfied ? COL_SATISFIED : COL_FOREGROUND, c);
- draw_update(dr, x - ds->tilesize/4 - 1, y - ds->tilesize/4 - 3,
- ds->tilesize/2 + 2, ds->tilesize/2 + 5);
-
- ds->clue_error[i] = clue_mistake;
- ds->clue_satisfied[i] = clue_satisfied;
+ /* Pass one is now done. Now we do the actual drawing. */
+ if (redraw_everything) {
+ int grid_width = g->highest_x - g->lowest_x;
+ int grid_height = g->highest_y - g->lowest_y;
+ int w = grid_width * ds->tilesize / g->tilesize;
+ int h = grid_height * ds->tilesize / g->tilesize;
- /* Sometimes, the bounding-box encroaches into the surrounding
- * lines (particularly if the window is resized fairly small).
- * So redraw them. */
- for (j = 0; j < f->order; j++)
- ds->lines[f->edges[j] - g->edges] = -1;
- }
- }
+ game_redraw_in_rect(dr, ds, state,
+ 0, 0, w + 2*border + 1, h + 2*border + 1);
+ } else {
- /* I've also had a request to colour lines red if they make a non-solution
- * loop, or if more than two lines go into any point. I think that would
- * be good some time. */
+ /* Right. Now we roll up our sleeves. */
- /* Lines */
- for (i = 0; i < g->num_edges; i++) {
- grid_edge *e = g->edges + i;
- int x1, x2, y1, y2;
- int xmin, ymin, xmax, ymax;
- int need_draw = (state->lines[i] != ds->lines[i]) ? TRUE : FALSE;
- if (flash_changed && (state->lines[i] == LINE_YES))
- need_draw = TRUE;
- if (!ds->started)
- need_draw = TRUE; /* draw everything at the start */
- ds->lines[i] = state->lines[i];
- if (!need_draw)
- continue;
- if (state->lines[i] == LINE_UNKNOWN)
- line_colour = COL_LINEUNKNOWN;
- else if (state->lines[i] == LINE_NO)
- line_colour = COL_BACKGROUND;
- else if (ds->flashing)
- line_colour = COL_HIGHLIGHT;
- else
- line_colour = COL_FOREGROUND;
+ for (i = 0; i < nfaces; i++) {
+ grid_face *f = g->faces + faces[i];
+ int x, y, w, h;
- /* Convert from grid to screen coordinates */
- grid_to_screen(ds, g, e->dot1->x, e->dot1->y, &x1, &y1);
- grid_to_screen(ds, g, e->dot2->x, e->dot2->y, &x2, &y2);
+ face_text_bbox(ds, g, f, &x, &y, &w, &h);
+ game_redraw_in_rect(dr, ds, state, x, y, w, h);
+ }
- xmin = min(x1, x2);
- xmax = max(x1, x2);
- ymin = min(y1, y2);
- ymax = max(y1, y2);
+ for (i = 0; i < nedges; i++) {
+ grid_edge *e = g->edges + edges[i];
+ int x, y, w, h;
- if (line_colour != COL_BACKGROUND) {
- /* (dx, dy) points roughly from (x1, y1) to (x2, y2).
- * The line is then "fattened" in a (roughly) perpendicular
- * direction to create a thin rectangle. */
- int dx = (x1 > x2) ? -1 : ((x1 < x2) ? 1 : 0);
- int dy = (y1 > y2) ? -1 : ((y1 < y2) ? 1 : 0);
- int points[] = {
- x1 + dy, y1 - dx,
- x1 - dy, y1 + dx,
- x2 - dy, y2 + dx,
- x2 + dy, y2 - dx
- };
- draw_polygon(dr, points, 4, line_colour, line_colour);
- }
- if (ds->started) {
- /* Draw dots at ends of the line */
- draw_circle(dr, x1, y1, 2, COL_FOREGROUND, COL_FOREGROUND);
- draw_circle(dr, x2, y2, 2, COL_FOREGROUND, COL_FOREGROUND);
- }
- draw_update(dr, xmin-2, ymin-2, xmax - xmin + 4, ymax - ymin + 4);
+ edge_bbox(ds, g, e, &x, &y, &w, &h);
+ game_redraw_in_rect(dr, ds, state, x, y, w, h);
+ }
}
- /* Draw dots */
- if (!ds->started) {
- for (i = 0; i < g->num_dots; i++) {
- grid_dot *d = g->dots + i;
- int x, y;
- grid_to_screen(ds, g, d->x, d->y, &x, &y);
- draw_circle(dr, x, y, 2, COL_FOREGROUND, COL_FOREGROUND);
- }
- }
ds->started = TRUE;
}
-static float game_flash_length(game_state *oldstate, game_state *newstate,
- int dir, game_ui *ui)
+static float game_flash_length(const game_state *oldstate,
+ const game_state *newstate, int dir, game_ui *ui)
{
if (!oldstate->solved && newstate->solved &&
!oldstate->cheated && !newstate->cheated) {
return 0.0F;
}
-static void game_print_size(game_params *params, float *x, float *y)
+static int game_status(const game_state *state)
+{
+ return state->solved ? +1 : 0;
+}
+
+static void game_print_size(const game_params *params, float *x, float *y)
{
int pw, ph;
*y = ph / 100.0F;
}
-static void game_print(drawing *dr, game_state *state, int tilesize)
+static void game_print(drawing *dr, const game_state *state, int tilesize)
{
int ink = print_mono_colour(dr, 0);
int i;
game_drawstate ads, *ds = &ads;
grid *g = state->game_grid;
- game_set_size(dr, ds, NULL, tilesize);
+ ds->tilesize = tilesize;
+ ds->textx = snewn(g->num_faces, int);
+ ds->texty = snewn(g->num_faces, int);
+ for (i = 0; i < g->num_faces; i++)
+ ds->textx[i] = ds->texty[i] = -1;
for (i = 0; i < g->num_dots; i++) {
int x, y;
grid_face *f = g->faces + i;
int clue = state->clues[i];
if (clue >= 0) {
- char c[2];
+ char c[20];
int x, y;
- c[0] = CLUE2CHAR(clue);
- c[1] = '\0';
+ sprintf(c, "%d", state->clues[i]);
face_text_pos(ds, g, f, &x, &y);
draw_text(dr, x, y,
FONT_VARIABLE, ds->tilesize / 2,
double d = sqrt(SQ((double)x1 - x2) + SQ((double)y1 - y2));
double dx = (x2 - x1) / d;
double dy = (y2 - y1) / d;
+ int points[8];
+
dx = (dx * ds->tilesize) / thickness;
dy = (dy * ds->tilesize) / thickness;
- int points[] = {
- x1 + dy, y1 - dx,
- x1 - dy, y1 + dx,
- x2 - dy, y2 + dx,
- x2 + dy, y2 - dx
- };
+ points[0] = x1 + (int)dy;
+ points[1] = y1 - (int)dx;
+ points[2] = x1 - (int)dy;
+ points[3] = y1 + (int)dx;
+ points[4] = x2 - (int)dy;
+ points[5] = y2 + (int)dx;
+ points[6] = x2 + (int)dy;
+ points[7] = y2 - (int)dx;
draw_polygon(dr, points, 4, ink, ink);
}
else
}
}
}
+
+ sfree(ds->textx);
+ sfree(ds->texty);
}
#ifdef COMBINED
game_redraw,
game_anim_length,
game_flash_length,
+ game_status,
TRUE, FALSE, game_print_size, game_print,
FALSE /* wants_statusbar */,
FALSE, game_timing_state,
0, /* mouse_priorities */
};
+
+#ifdef STANDALONE_SOLVER
+
+/*
+ * Half-hearted standalone solver. It can't output the solution to
+ * anything but a square puzzle, and it can't log the deductions
+ * it makes either. But it can solve square puzzles, and more
+ * importantly it can use its solver to grade the difficulty of
+ * any puzzle you give it.
+ */
+
+#include <stdarg.h>
+
+int main(int argc, char **argv)
+{
+ game_params *p;
+ game_state *s;
+ char *id = NULL, *desc, *err;
+ int grade = FALSE;
+ int ret, diff;
+#if 0 /* verbose solver not supported here (yet) */
+ int really_verbose = FALSE;
+#endif
+
+ while (--argc > 0) {
+ char *p = *++argv;
+#if 0 /* verbose solver not supported here (yet) */
+ if (!strcmp(p, "-v")) {
+ really_verbose = TRUE;
+ } else
+#endif
+ if (!strcmp(p, "-g")) {
+ grade = TRUE;
+ } else if (*p == '-') {
+ fprintf(stderr, "%s: unrecognised option `%s'\n", argv[0], p);
+ return 1;
+ } else {
+ id = p;
+ }
+ }
+
+ if (!id) {
+ fprintf(stderr, "usage: %s [-g | -v] <game_id>\n", argv[0]);
+ return 1;
+ }
+
+ desc = strchr(id, ':');
+ if (!desc) {
+ fprintf(stderr, "%s: game id expects a colon in it\n", argv[0]);
+ return 1;
+ }
+ *desc++ = '\0';
+
+ p = default_params();
+ decode_params(p, id);
+ err = validate_desc(p, desc);
+ if (err) {
+ fprintf(stderr, "%s: %s\n", argv[0], err);
+ return 1;
+ }
+ s = new_game(NULL, p, desc);
+
+ /*
+ * When solving an Easy puzzle, we don't want to bother the
+ * user with Hard-level deductions. For this reason, we grade
+ * the puzzle internally before doing anything else.
+ */
+ ret = -1; /* placate optimiser */
+ for (diff = 0; diff < DIFF_MAX; diff++) {
+ solver_state *sstate_new;
+ solver_state *sstate = new_solver_state((game_state *)s, diff);
+
+ sstate_new = solve_game_rec(sstate);
+
+ if (sstate_new->solver_status == SOLVER_MISTAKE)
+ ret = 0;
+ else if (sstate_new->solver_status == SOLVER_SOLVED)
+ ret = 1;
+ else
+ ret = 2;
+
+ free_solver_state(sstate_new);
+ free_solver_state(sstate);
+
+ if (ret < 2)
+ break;
+ }
+
+ if (diff == DIFF_MAX) {
+ if (grade)
+ printf("Difficulty rating: harder than Hard, or ambiguous\n");
+ else
+ printf("Unable to find a unique solution\n");
+ } else {
+ if (grade) {
+ if (ret == 0)
+ printf("Difficulty rating: impossible (no solution exists)\n");
+ else if (ret == 1)
+ printf("Difficulty rating: %s\n", diffnames[diff]);
+ } else {
+ solver_state *sstate_new;
+ solver_state *sstate = new_solver_state((game_state *)s, diff);
+
+ /* If we supported a verbose solver, we'd set verbosity here */
+
+ sstate_new = solve_game_rec(sstate);
+
+ if (sstate_new->solver_status == SOLVER_MISTAKE)
+ printf("Puzzle is inconsistent\n");
+ else {
+ assert(sstate_new->solver_status == SOLVER_SOLVED);
+ if (s->grid_type == 0) {
+ fputs(game_text_format(sstate_new->state), stdout);
+ } else {
+ printf("Unable to output non-square grids\n");
+ }
+ }
+
+ free_solver_state(sstate_new);
+ free_solver_state(sstate);
+ }
+ }
+
+ return 0;
+}
+
+#endif
+
+/* vim: set shiftwidth=4 tabstop=8: */
~ian / sgt-puzzles.git / blobdiff