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Fixed #105 - Opening explorer on a filename with a space in it failed.
author
daid
<daid303@gmail.com>
Tue, 15 May 2012 11:18:38 +0000
(13:18 +0200)
committer
daid
<daid303@gmail.com>
Tue, 15 May 2012 11:18:38 +0000
(13:18 +0200)
Cura/util/exporer.py
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diff --git
a/Cura/util/exporer.py
b/Cura/util/exporer.py
index 8fcc65faad353739163a25b8b2a77f23b827eb58..5eca1416bbcefff292b36eab033c2e3108ad560d 100644
(file)
--- a/
Cura/util/exporer.py
+++ b/
Cura/util/exporer.py
@@
-15,7
+15,7
@@
def hasExporer():
def openExporer(filename):
if sys.platform == 'win32' or sys.platform == 'cygwin':
- subprocess.Popen(
['explorer', "/select,%s" % (filename)]
)
+ subprocess.Popen(
r'explorer /select,"%s"' % (filename)
)
if sys.platform == 'darwin':
subprocess.Popen(['open', os.path.split(filename)[0]])
if sys.platform == 'linux2':