From 54fc3c8f829bfae8dfba6b2178228d2e80036722 Mon Sep 17 00:00:00 2001
From: Ian Jackson <ijackson@chiark.greenend.org.uk>
Date: Wed, 21 Mar 2012 18:22:59 +0000
Subject: [PATCH 1/1] simple commit fix P notation

---
 simple.tex | 10 +++++-----
 1 file changed, 5 insertions(+), 5 deletions(-)

diff --git a/simple.tex b/simple.tex
index 28dc6e5..9b556ed 100644
--- a/simple.tex
+++ b/simple.tex
@@ -51,7 +51,7 @@ $\qed$
 
 Need to consider $D \in \py$
 
-\subsubsection{For $L \haspatch P, D = C$:}
+\subsubsection{For $L \haspatch \p, D = C$:}
 
 Ancestors of $C$:
 $ D \le C $.
@@ -59,16 +59,16 @@ $ D \le C $.
 Contents of $C$:
 $ D \isin C \equiv \ldots \lor \true \text{ so } D \haspatch C $.
 
-\subsubsection{For $L \haspatch P, D \neq C$:}
+\subsubsection{For $L \haspatch \p, D \neq C$:}
 Ancestors: $ D \le C \equiv D \le L $.
 
 Contents: $ D \isin C \equiv D \isin L \lor f $
 so $ D \isin C \equiv D \isin L $.
 
 So:
-\[ L \haspatch P \implies C \haspatch P \]
+\[ L \haspatch \p \implies C \haspatch \p \]
 
-\subsubsection{For $L \nothaspatch P$:}
+\subsubsection{For $L \nothaspatch \p$:}
 
 Firstly, $C \not\in \py$ since if it were, $L \in \py$.
 Thus $D \neq C$.
@@ -76,7 +76,7 @@ Thus $D \neq C$.
 Now by contents of $L$, $D \notin L$, so $D \notin C$.
 
 So:
-\[ L \nothaspatch P \implies C \nothaspatch P \]
+\[ L \nothaspatch \p \implies C \nothaspatch \p \]
 $\qed$
 
 \subsection{Foreign Inclusion:}
-- 
2.30.2