Consider some $D$ s.t. $\patchof{D} = \bot$. $D \neq C$.
So by Desired Contents $D \isin C \equiv D \isin L$.
By Foreign Inclusion of $D$ in $L$, $D \isin L \equiv D \le L$.
-So $D \isin C \equiv D \le L$.
-xxx up to here
-
-By Tip Contents of $R^+$, $D \isin R^+ \equiv D \isin \baseof{R^+}$
-i.e. $\equiv D \isin R^-$.
-So by $\merge$, $D \isin C \equiv D \isin L$.
-
-Thus $D \isin C \equiv $
+And $D \le C \equiv D \le L$.
+Thus $D \isin C \equiv D \le C$. $\qed$
\section{Merge}