If $\patchof{L} = \pa{L}$, trivial by Base Acyclic for $L$.
-If $\patchof{L} = \bot$, xxx
-
-Trivial from Base Acyclic for $L$. $\qed$
+If $\patchof{L} = \bot$, consider some $D \isin B$. $D \neq B$.
+Thus $D \isin L$. So by No Replay of $D$ in $L$, $D \le L$.
+Thus $D \le B$.
\subsection{Unique Base}
\subsection{Base Acyclic}
-xxx
+Consider some $D \isin B$. If $D = B$, $D \in \pn$, OK.
+
+If $D \neq B$, $D \isin L$. By No Replay of $D$ in $L$, $D \le L$.
+Thus by Foreign Contents of $L$, $\patchof{D} = \bot$. OK.
+
+$\qed$
+
+\subsection{Coherence and Patch Inclusion}
+
+Consider some $D \in \p$.
+$B \not\in \py$ so $D \neq B$. So $D \isin B \equiv D \isin L$.
+
+Thus $L \haspatch \p \implies B \haspatch P$
+and $L \nothaspatch \p \implies B \nothaspatch P$.
+
+$\qed$.
xxx unfinished