X-Git-Url: http://www.chiark.greenend.org.uk/ucgi/~ian/git?p=topbloke-formulae.git;a=blobdiff_plain;f=simple.tex;h=5f6e184aad199a55782ac4c8e2884d632fa05663;hp=ae6fc5551fd797dedeeeced6423cf5708b0d0f05;hb=cb5a9d3227f121506751f47f098e53ced767a278;hpb=b1adf56763bea8bb31f2b2113b0718be0dd0bc3a

diff --git a/simple.tex b/simple.tex
index ae6fc55..5f6e184 100644
--- a/simple.tex
+++ b/simple.tex
@@ -56,7 +56,6 @@ $$
 \end{cases}
 $$
 \proofstarts
-~
 
 Firstly, if $L \haspatch \p$, $\exists_{F \in \py} F \le L$
 and this $F$ is also $\le C$
@@ -79,13 +78,14 @@ Ancestors: $ D \le C \equiv D \le L $.
 
 Contents: $ D \isin C \equiv D \isin L \lor f $
 so $ D \isin C \equiv D \isin L $, i.e. $ C \zhaspatch P $.
+OK.
 
 \subsubsection{For $L \nothaspatch \p$:}
 
 Firstly, $C \not\in \py$ since if it were, $L \in \py$.
 Thus $D \neq C$.
 
-Now by contents of $L$, $D \notin L$, so $D \notin C$.
+Now by $\nothaspatch$, $D \not\isin L$ so $D \not\isin C$.
 OK.
 
 $\qed$