X-Git-Url: http://www.chiark.greenend.org.uk/ucgi/~ian/git?p=topbloke-formulae.git;a=blobdiff_plain;f=anticommit.tex;h=49931279917b36872d16a2f179788458ee4a7d17;hp=90f2ea40a59b76e782e2466d123754946af4c228;hb=8a69195a6c694ebddaf1d383ca0301041b05c2b4;hpb=8922ddb1523c8785fadbc19d130eeea0c71b2b71 diff --git a/anticommit.tex b/anticommit.tex index 90f2ea4..4993127 100644 --- a/anticommit.tex +++ b/anticommit.tex @@ -8,7 +8,7 @@ Used for removing a branch dependency. \gathnext \patchof{C} = \patchof{L} \gathnext - \mergeof{C}{L}{R^+}{R^-} + \commitmergeof{C}{L}{R^+}{R^-} \end{gather} \subsection{Conditions} @@ -19,7 +19,7 @@ R^+ \in \pry \land R^- = \baseof{R^+} \[ \eqn{ Into Base }{ L \in \pln }\] -\[ \eqn{ Unique Tip }{ +\[ \eqn{ Correct Tip }{ \pendsof{L}{\pry} = \{ R^+ \} }\] \[ \eqn{ Currently Included }{ @@ -28,7 +28,7 @@ R^+ \in \pry \land R^- = \baseof{R^+} \subsection{Ordering of Ingredients:} -By Unique Tip, $R^+ \le L$. By definition of $\base$, $R^- \le R^+$ +By Correct Tip, $R^+ \le L$. By definition of $\base$, $R^- \le R^+$ so $R^- \le L$. So $R^+ \le C$ and $R^- \le C$. $\qed$ @@ -37,7 +37,7 @@ is a descendant, not an ancestor, of the 2nd parent.) \subsection{No Replay} -By $\merge$, +By \commitmergename, $D \isin C \implies D \isin L \lor D \isin R^- \lor D = C$. So, by Ordering of Ingredients, Ingredients Prevent Replay applies. $\qed$ @@ -61,19 +61,19 @@ $D \not\isin R^-$. Thus $D \not\isin C$. OK. By Currently Included, $D \isin L$. -By Tip Own Contents for $R^+$, $D \isin R^+ \equiv D \le R^+$, but by -by Unique Tip, $D \le R^+ \equiv D \le L$. +By Tip Own Contents for $R^+$, $D \isin R^+ \equiv D \le R^+$, but +by Correct Tip, $D \le R^+ \equiv D \le L$. So $D \isin R^+$. By Base Acyclic for $R^-$, $D \not\isin R^-$. -Apply $\merge$: $D \not\isin C$. OK. +Apply \commitmergename: $D \not\isin C$. OK. \subsubsection{For $D \neq C, D \le L, D \notin \pry$:} By Tip Contents for $R^+$, $D \isin R^+ \equiv D \isin R^-$. -Apply $\merge$: $D \isin C \equiv D \isin L$. OK. +Apply \commitmergename: $D \isin C \equiv D \isin L$. OK. $\qed$ @@ -125,9 +125,13 @@ OK. $\qed$ +\subsection{Unique Tips:} + +Single Parent Unique Tips applies. $\qed$ + \subsection{Foreign Inclusion} -Consider some $D$ s.t. $\patchof{D} = \bot$. $D \neq C$. +Consider some $D \in \foreign$. $D \neq C$. So by Desired Contents $D \isin C \equiv D \isin L$. By Foreign Inclusion of $D$ in $L$, $D \isin L \equiv D \le L$.