a possible bug

[topbloke-formulae.git] / article.tex

diff --git a/article.tex b/article.tex
index 7e78f9b647efd8b2b1d2d76f7294244474b2d955..b0a14f254ff6a6835b0269593c733b6854f21e67 100644 (file)
--- a/article.tex
+++ b/article.tex
@@ -1,4 +1,5 @@
 \documentclass[a4paper,leqno]{strayman}
+\errorcontextlines=50
 \let\numberwithin=\notdef
 \usepackage{amsmath}
 \usepackage{mathabx}
@@ -21,9 +22,9 @@
         \newif\ifhidehack\hidehackfalse
         \DeclareRobustCommand\hidefromedef[2]{%
           \hidehacktrue\ifhidehack#1\else#2\fi\hidehackfalse}
-        \newcommand{\pa}[1]{\hidefromedef{\varmathbb #1}{#1}}
+        \newcommand{\pa}[1]{\hidefromedef{\varmathbb{#1}}{#1}}
 
-\newcommand{\set}[1]{\mathbb #1}
+\newcommand{\set}[1]{\mathbb{#1}}
 \newcommand{\pay}[1]{\pa{#1}^+}
 \newcommand{\pan}[1]{\pa{#1}^-}
 
@@ -395,7 +396,7 @@ putative ancestor $A \in \pn$ and see whether $A \le C$.
 
 $A \le C \equiv A \le L \lor A \le R \lor A = C$.
 But $C \in py$ and $A \in \pn$ so $A \neq C$.  
-Thus $A \le L \lor A \le R$.
+Thus $fixme this is not really the right thing A \le L \lor A \le R$.
 
 By Unique Base of L and Transitive Ancestors,
 $A \le L \equiv A \le \baseof{L}$.