If $\patchof{L} = \pa{L}$, trivial by Base Acyclic for $L$.
-If $\patchof{L} = \bot$, xxx
-
-Trivial from Base Acyclic for $L$. $\qed$
+If $\patchof{L} = \bot$, consider some $D \isin B$. $D \neq B$.
+Thus $D \isin L$. So by No Replay of $D$ in $L$, $D \le L$.
+Thus $D \le B$.
\subsection{Unique Base}
-Not applicable. $\qed$
+Not applicable.
\subsection{Tip Contents}
-Not applicable. $\qed$
+Not applicable.
\subsection{Base Acyclic}
-xxx
+Consider some $D \isin B$. If $D = B$, $D \in \pn$, OK.
+
+If $D \neq B$, $D \isin L$. By No Replay of $D$ in $L$, $D \le L$.
+Thus by Foreign Contents of $L$, $\patchof{D} = \bot$. OK.
+
+$\qed$
+
+\subsection{Coherence and Patch Inclusion}
+
+Consider some $D \in \p$.
+$B \not\in \py$ so $D \neq B$. So $D \isin B \equiv D \isin L$.
+
+Thus $L \haspatch \p \implies B \haspatch P$
+and $L \nothaspatch \p \implies B \nothaspatch P$.
+
+$\qed$.
+
+\subsection{Foreign Inclusion}
+
+Consider some $D$ s.t. $\patchof{D} = \bot$. $D \neq B$
+so $D \isin B \equiv D \isin L$.
+By Foreign Inclusion of $D$ in $L$, $D \isin L \equiv D \le L$.
+And by Exact Ancestors $D \le L \equiv D \le B$.
+So $D \isin B \equiv D \le B$. $\qed$
+
+\subsection{Foreign Contents}
-xxx unfinished
+Not applicable.
\section{Create Tip}
L \haspatch \pry
}\]
-\subsection{Ordering of ${L, R^+, R^-}$:}
+\subsection{Ordering of Ingredients:}
By Unique Tip, $R^+ \le L$. By definition of $\base$, $R^- \le R^+$
so $R^- \le L$. So $R^+ \le C$ and $R^- \le C$.
\subsection{Foreign Contents}
-Not applicable. $\qed$
+Not applicable.
\section{Merge}