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[topbloke-formulae.git] / article.tex

diff --git a/article.tex b/article.tex
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--- a/article.tex
+++ b/article.tex
@@ -408,10 +408,12 @@ $A \le R \equiv A \le \baseof{R}$.
 
 But by Tip Merge condition on $\baseof{R}$,
 $A \le \baseof{L} \implies A \le \baseof{R}$, so
-$A \le \baseof{R} \lor A \le \baseof{R} \equiv A \le \baseof{R}$.
+$A \le \baseof{R} \lor A \le \baseof{L} \equiv A \le \baseof{R}$.
 Thus $A \le C \equiv A \le \baseof{R}$.  Ie, $\baseof{C} =
 \baseof{R}$.
 
+\subsubsection{For $R \in \pn$:}
+
 UP TO HERE
 
 By Tip Merge, $A \le $