If $L \nothaspatch \p$, $D \not\isin L$ so $D \not\isin C$.
So $L \nothaspatch \p \implies C \nothaspatch \p$.
-Whereas if $L \haspatch \p$, $D \isin L \equiv D \le L$.
-so $L \haspatch \p \implies C \zhaspatch \p$.
-fixme up to here pdf page 13
+Whereas, if $L \haspatch \p$, $D \isin L \equiv D \le L$,
+so $C \zhaspatch \p$;
+and $\exists_{F \in \py} F \le L$ so this $F \le C$.
+Thus $\p \neq R \land L \haspatch \p \implies C \haspatch \p$.
$\qed$