From: Ian Jackson <ijackson@chiark.greenend.org.uk>
Date: Mon, 12 Mar 2012 18:04:51 +0000 (+0000)
Subject: more clarifications and fixes from reread
X-Git-Tag: f0.2~36
X-Git-Url: http://www.chiark.greenend.org.uk/ucgi/~ian/git?a=commitdiff_plain;ds=sidebyside;h=e090a73b6d5a31fae5d7bc1244ea8defdeabae05;p=topbloke-formulae.git

more clarifications and fixes from reread
---

diff --git a/article.tex b/article.tex
index 70cee81..4af8e05 100644
--- a/article.tex
+++ b/article.tex
@@ -676,7 +676,7 @@ Used for removing a branch dependency.
 R^+ \in \pry \land R^- = \baseof{R^+}
 }\]
 \[ \eqn{ Into Base }{
- L \in \pn
+ L \in \pqn
 }\]
 \[ \eqn{ Unique Tip }{
  \pendsof{L}{\pry} = \{ R^+ \}
@@ -696,7 +696,7 @@ is a descendant, not an ancestor, of the 2nd parent.)
 
 \subsection{No Replay}
 
-By definition of $\merge$,
+By $\merge$,
 $D \isin C \implies D \isin L \lor D \isin R^- \lor D = C$.
 So, by Ordering of Ingredients,
 Ingredients Prevent Replay applies.  $\qed$
@@ -712,7 +712,8 @@ Trivially $D \isin C$.  OK.
 
 \subsubsection{For $D \neq C, D \not\le L$:}
 
-By No Replay $D \not\isin L$.  Also $D \not\le R^-$ hence
+By No Replay for $L$, $D \not\isin L$.
+Also, by Ordering of Ingredients, $D \not\le R^-$ hence
 $D \not\isin R^-$.  Thus $D \not\isin C$.  OK.
 
 \subsubsection{For $D \neq C, D \le L, D \in \pry$:}
@@ -723,7 +724,7 @@ By Tip Self Inpatch for $R^+$, $D \isin R^+ \equiv D \le R^+$, but by
 by Unique Tip, $D \le R^+ \equiv D \le L$.
 So $D \isin R^+$.
 
-By Base Acyclic, $D \not\isin R^-$.
+By Base Acyclic for $R^-$, $D \not\isin R^-$.
 
 Apply $\merge$: $D \not\isin C$.  OK.
 
@@ -737,7 +738,7 @@ $\qed$
 
 \subsection{Unique Base}
 
-Into Base means that $C \in \pn$, so Unique Base is not
+Into Base means that $C \in \pqn$, so Unique Base is not
 applicable. $\qed$
 
 \subsection{Tip Contents}
@@ -746,11 +747,11 @@ Again, not applicable. $\qed$
 
 \subsection{Base Acyclic}
 
-By Base Acyclic for $L$, $D \isin L \implies D \not\in \py$.
-And by Into Base $C \not\in \py$.
+By Into Base and Base Acyclic for $L$, $D \isin L \implies D \not\in \pqy$.
+And by Into Base $C \not\in \pqy$.
 Now from Desired Contents, above, $D \isin C
 \implies D \isin L \lor D = C$, which thus
-$\implies D \not\in \py$.  $\qed$.
+$\implies D \not\in \pqy$.  $\qed$.
 
 \subsection{Coherence and Patch Inclusion}