a possible bug

[topbloke-formulae.git] / article.tex

diff --git a/article.tex b/article.tex
index f0bbf33b91975bcb61866b8eeef73fabcea17af2..b0a14f254ff6a6835b0269593c733b6854f21e67 100644 (file)
--- a/article.tex
+++ b/article.tex
@@ -1,4 +1,5 @@
 \documentclass[a4paper,leqno]{strayman}
+\errorcontextlines=50
 \let\numberwithin=\notdef
 \usepackage{amsmath}
 \usepackage{mathabx}
@@ -18,8 +19,12 @@
 \newcommand{\haspatch}{\sqSupset}
 \newcommand{\patchisin}{\sqSubset}
 
-\newcommand{\set}[1]{\mathbb #1}
-\newcommand{\pa}[1]{\varmathbb #1}
+        \newif\ifhidehack\hidehackfalse
+        \DeclareRobustCommand\hidefromedef[2]{%
+          \hidehacktrue\ifhidehack#1\else#2\fi\hidehackfalse}
+        \newcommand{\pa}[1]{\hidefromedef{\varmathbb{#1}}{#1}}
+
+\newcommand{\set}[1]{\mathbb{#1}}
 \newcommand{\pay}[1]{\pa{#1}^+}
 \newcommand{\pan}[1]{\pa{#1}^-}
 
@@ -391,7 +396,7 @@ putative ancestor $A \in \pn$ and see whether $A \le C$.
 
 $A \le C \equiv A \le L \lor A \le R \lor A = C$.
 But $C \in py$ and $A \in \pn$ so $A \neq C$.  
-Thus $A \le L \lor A \le R$.
+Thus $fixme this is not really the right thing A \le L \lor A \le R$.
 
 By Unique Base of L and Transitive Ancestors,
 $A \le L \equiv A \le \baseof{L}$.
@@ -417,7 +422,7 @@ Let $S =
      R \in \pn : & R
    \end{cases}$.  
 Then by Tip Merge $S \ge \baseof{L}$, and $R \ge S$ so $C \ge S$.
-    
+   
 Consider some $A \in \pn$.  If $A \le S$ then $A \le C$.
 If $A \not\le S$ then 
 
@@ -430,6 +435,5 @@ Then by Calculation Of Ends $A \in \pendsof{L,\pn} \lor A \in
 %$\pends{C,
 
 %%\subsubsection{For $R \in \py$:}
-%foo
 
 \end{document}