+
+\subsection{Bases' Children}
+
+We need to consider this for $D=L$ and also for $D=R$ ($R \in \set
+R$).
+
+For $D=L$: $L \in \pn$ so $\pd = \p$. And $C \in \pn = \pdn$. Bases'
+Children applies and is satisfied.
+
+For $D = R \in \set R, R \in \pn$: $D \in \pn, \pd = \p, C \in \pn$ as
+for $D = L$.
+
+For $D = R \in \set R, R \in \foreign$, or $R \in \pqy$: $D \not\in
+\pdn$ so Bases' Children does not apply.
+
+Other possibilities for $D \in \set R$ are excluded by Ingredients.